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2 years ago

Evaluate the function for the indicated input

Mathematics

1 answer:

Ilya [14]2 years ago

4 0

$f(0)=0^2+0-6=\boxed{-6}$ .

Hope this helps.

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The open intervals on which f is concave upward. (enter your answer using interval notation.

N76 [4]

Khan academy has a lot on this sorry I couldn't answer bro

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3 years ago

What can 23/40 be simplified by?

kicyunya [14]

23/40 can't be simplified as it has no common factors

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3 years ago

Which expression uses the associative property to make it easier to evaluate? (50points)

Naily [24]

The correct answer is option 4: $(8.\frac{1}{4}).\frac{3}{5}$

Step-by-step explanation:

Given expression is:

$8.(\frac{1}{4}.\frac{3}{5})$

The associative property states that for any three terms that are being multiplied, different order of multiplication (i.e. which two terms are multiplied first) will give the same answer.

Let a,b and c be the three terms

then

$a.(b.c) = (a.b).c$

So applying the associative property on given expression

$8.(\frac{1}{4}.\frac{3}{5}) = (8.\frac{1}{4}).\frac{3}{5}$

Hence,

The correct answer is option 4: $(8.\frac{1}{4}).\frac{3}{5}$

Keywords: Associative property, Properties

Learn more about associative property at:

#learnwithBrainly

5 0

3 years ago

Factor: k^2 + 7x + 10<br> A:(k+10)(k+4)<br> B:(k+2)(k+5)<br> C:(k+2)(k-5)<br> D:(k-2)(k-5)

Nata [24]

Answer:

the answer is B. (k+2)(k+5)

7 0

2 years ago

Read 2 more answers

What is the 6th term of the geometric sequence where a1 = -4096 and a4 = 64?

Akimi4 [234]

$\bf \begin{array}{llccll}
term&value\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
a_1&-4096\\
a_2&-4096r\\
a_3&-4096rr\\
a_4&-4096rrr\\
&-4096r^3\\
&64
\end{array}\implies -4096r^3=64
\\\\\\
r^3=\cfrac{64}{-4096}\implies r^3=-\cfrac{1}{64}\implies r=\sqrt[3]{-\cfrac{1}{64}}
\\\\\\
r=\cfrac{\sqrt[3]{-1}}{\sqrt[3]{64}}\implies \boxed{r=\cfrac{-1}{4}}\\\\
-------------------------------$

$\bf n^{th}\textit{ term of a geometric sequence}\\\\
a_n=a_1\cdot r^{n-1}\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
r=\textit{common ratio}\\
----------\\
r=-\frac{1}{4}\\
a_1=-4096\\
n=6
\end{cases}
\\\\\\
a_6=-4096\left( -\frac{1}{4} \right)^{6-1}\implies a_6=-4^6\left( -\frac{1}{4} \right)^5$

4 0

2 years ago

Read 2 more answers