F=9/5C+32
rewrite as 9/5C+32=F
9/5C+32-32=F-32
9/5C=F-32
(5*9/5)C=(F-32)*5
9C=5F-160
9/9C=(5F-160)/9
C=(5F-160)/9
The answer is 3 to subtract the fractions, find the LCD and then combine
Cos(angle) = Adjacent Leg / Hypotenuse
cos(35) = 9 / x
x = 9 / cos(35)
x = 10.99
Rounded to nearest tenth = 11.0
Answer:

Step-by-step explanation:
<u>Formula for area of rectangle:</u>
= length × width
<u>Area of the smaller rectangle:</u>
length = 7
width = 6
= 7 × 6
= 42
<u>Area of the larger rectangle:</u>
length = 7 + 4 = 11
width = 6 + 2 = 8
= 11 × 8
= 88
<u>Area of the shaded region:</u>
= Area of the larger rectangle - Area of the smaller rectangle
= 88 - 42
= 46
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
A) One solution: 5x +2y = 0 . . . . (any line with a different slope)
b) Two solutions: not possible
c) No solutions: 5x -2y = 0 . . . . (any different line with the same slope)
d) Infinitely many solutions: 10x -4y = 6 . . . . (any other equation for the same line)