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3 years ago

Heydhdhcjhcjkhcjhkhjckzhuisehzcwjkhzxuichslhcuihzuca

Mathematics

2 answers:

Hunter-Best [27]3 years ago

3 0

Answer:

owduifbeiprnjviruvhneijwvbierubvjkrewn rfv

Step-by-step explanation:

pochemuha3 years ago

3 0

Answer:

Have a proper question please-

Step-by-step explanation:

Did you know that

heydhdhcjhcjkhcjhkhjckzhuisehzcwjkhzxuichslhcuihzuca is

01101000 01100101 01111001 01100100 01101000 01100100 01101000 01100011 01101010 01101000 01100011 01101010 01101011 01101000 01100011 01101010 01101000 01101011 01101000 01101010 01100011 01101011 01111010 01101000 01110101 01101001 01110011 01100101 01101000 01111010 01100011 01110111 01101010 01101011 01101000 01111010 01111000 01110101 01101001 01100011 01101000 01110011 01101100 01101000 01100011 01110101 01101001 01101000 01111010 01110101 01100011 01100001

In binary? Thought I might as well make use of the free points.

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Consider the following hypothesis test. H0: μ ≥ 55 Ha: μ < 55 A sample of 36 is used. Identify the p-value and state your con

Ket [755]

Answer:

Step-by-step explanation:

Given that:

$H_o: \mu \ge 55 \ \\ \\ H_1 : \mu < 55$

(a) For x = 54 and s = 5.3

The test statistics can be computed as:

$Z = \dfrac{\overline x - \mu}{\dfrac{s}{\sqrt{n}} }$

$Z = \dfrac{54-55}{\dfrac{5.3}{\sqrt{36}} }$

$Z = \dfrac{-1}{\dfrac{5.3}{6} }$

Z = -1.132

degree of freedom = n - 1

= 36 - 1

= 35

Using the Excel Formula:

P-Value = T.DIST(-1.132,35,1) = 0.1326

Decision: p-value is greater than significance level; do not reject $\mathbf{H_o}$

$Conclusion: \ There \ is \ insufficient \ evidence \ to \ conclude \ that \$ $\mu < 55$

For x = 53 and s = 4.6

The test statistics can be computed as:

$Z = \dfrac{\overline x - \mu}{\dfrac{s}{\sqrt{n}} }$

$Z = \dfrac{53-55}{\dfrac{4.6}{\sqrt{36}} }$

$Z = \dfrac{-2}{\dfrac{4.6}{6} }$

Z = -2.6087

degree of freedom = n - 1

= 36 - 1

= 35

Using the Excel Formula:

P-Value = T.DIST(-2.6087,35,1) =0.0066

Decision: p-value is < significance level; we reject the null hypothesis.

$Conclusion: \ There \ is \ sufficient \ evidence \ to \ conclude \ that$ $\mu < 55$

For x = 56 and s = 5.0

The test statistics can be computed as:

$Z = \dfrac{\overline x - \mu}{\dfrac{s}{\sqrt{n}} }$

$Z = \dfrac{56-55}{\dfrac{5.0}{\sqrt{36}} }$

Z = 1.2

degree of freedom = n - 1

= 36 - 1

= 35

Using the Excel Formula:

P-Value = T.DIST(1.2,35,1) = 0.88009

Decision: p-value is greater than significance level; do not reject $\mathbf{H_o}$

$Conclusion: \ There \ is \ insufficient \ evidence \ to \ conclude \ that \$ $\mu < 55$

6 0

3 years ago

Hel[ppppppppppp brainliestt

Gekata [30.6K]

Answer: I think it is 10364 or 10248 because when i put it in a calculator I got 8803.4 or 10296

Step-by-step explanation:

3 0

3 years ago

Show that the equation x^4/2021 − 2021x^2 − x − 3 = 0 has at least two real roots.

andreev551 [17]

The roots of an equation are simply the x-intercepts of the equation.

See below for the proof that $\mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0}$ has at least two real roots

The equation is given as: $\mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0}$

There are several ways to show that an equation has real roots, one of these ways is by using graphs.

See attachment for the graph of $\mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0}$

Next, we count the x-intercepts of the graph (i.e. the points where the equation crosses the x-axis)

From the attached graph, we can see that $\mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0}$ crosses the x-axis at approximately <em>-2000 and 2000 </em>between the domain -2500 and 2500

This means that $\mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0}$ has at least two real roots

Read more about roots of an equation at:

brainly.com/question/12912962

6 0

3 years ago

The midpoint of AB is M(4, -1). If the coordinates of A are (2,5), what are the

ozzi

Answer:

(6,-7)

Step-by-step explanation:

take b as x2,y2

then apply mid point formula

x=(x1+x2)/2

y=(y1+y2)/2

8 0

4 years ago

Read 2 more answers

Help me please !!!!!

barxatty [35]

Answer:

C.) Triangle TUV ~ Triangle WXY

Step-by-step explanation:

Find the angles that are equal in each triangle, and put them in the same position in the statement.

T and W are equal; therefore, they are first in each.

U and X are equal; therefore, they are second in each.

V and Y are equal; therfore, they are last in each.

4 0

3 years ago