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VLD [36.1K]
3 years ago
5

Four brothers each bought two hotdogs and a bag of chips at the concession stand.if the bag of chips was $1.25,and the total was

$18.20, what was the price of one hotdog
Mathematics
1 answer:
ahrayia [7]3 years ago
5 0

Answer:

  $1.65

Step-by-step explanation:

The total purchase can be described by ...

  4(2h +1.25) = 18.20 . . . . where h is the price of a hot dog

  8h = 13.20 . . . . . . . . . . . subtract 5.00

  h = 1.65 . . . . . divide by 8

The price of a hot dog was $1.65.

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In how many ways can 3 letters be mailed in 6 mailboxes if each letter must be mailed in a different box? If the letters are not
meriva

Answer:

Question 1: 120 ways

Question 2: 216 ways

Question 3: 1/36 = 0.278

Explanation:

<u>Question 1: In how many ways can 3 letters be mailed in 6 mailboxes if each letter must be mailed in a different box? </u>

The first letter may be mailed in any of the 6 mailboxes: 6

The second letter may be mailed in any of the other 5 mailboxes: 5

The third letter may be mailed in any of the other 4 mailboxes: 4

According to the fundamental counting principle, the total number of possible outcomes is the product of the possible outcomes for each event.

Thus, the number of ways 3 letters can be mailed in 6 mailboxes, if each letter must be mailed in a different box is 6 × 5 × 4 = 120.

<u>Question 2: If the letters are not necessarily mailed in different boxes, how many ways are there of posting them? </u>

Again, you must use the fundamental counting principle.

This time, since the letters are not necessarily mailed in different boxes, each one can be mailed in 6 boxes, and the total number of ways 3 letters can be mailed is:

  • 6 × 6 × 6 = 216.

<u>Question 3. If the letters are mailed at random, and not necessarily in different boxes, what is the probability that all the letters are put in the same mailbox?​</u>

<u></u>

The probability that all the letters are put in the same mailbox is:

  • number of favorable outcomes / number of total possible outcomes

  • number of favorable outcomes: 6

        This is: the three letters are mailed in the first mailbox, or the three letters in the second mailbox, or the three letters in the third mailbox, or the three letters in the fourth mailbox, or the three letters in the fifth mailbox, or the three letters in the sixth mailbox: 6.

  • number of total possible outcomes: 216 calculated in the question number 2.

  • probability = 6 / 216 = 1/36 = 0.278
3 0
3 years ago
Mr Lok is putting a pool in his backyard. His backyard is 10 m long and 8 m wide, while the pool he wants has an area of 8m2. ho
Olin [163]

Answer:

hope this helps and make me brainliest

Step-by-step explanation:

. You have that:

- The homeowner want the length of the swimming pool to be 4 feet longer than its width.

- He wants to surround it with a concrete walkway 3 feet wide.

- He can only afford 300 square feet of concrete for the walkway.

2. Therefore, the tota area is:

At=L2xW2

L2 is the lenght of the walkway (L2=L1+3+3⇒L2=(W1+4+6)⇒L2=W1+10).

W2 is the width of the walkway (W1+3+3⇒W2=W1+6)

3. The area of the walkway is:

A2=At-A1

A2=300 ft²

4. Therefore, you have that the width of the swimming pool is:

A2=(W1+10)(W1+6)-(W1+4)(W1)

300=(W1²+6W1+10W1+60)-(W1²+4W1)

W1²+16W1+60-W1²-4W1-300=0

12W1-240=0

W1=240/12

W1=20 ft

5. And the length is:

L1=W1+4

L1=20+4

L1=24 ft

4 0
2 years ago
Arrange the expression in increasing order of their values
maxonik [38]

Answer:

10⁰×10¹-1¹⁰ < 10⁰×10¹×1¹⁰ < 10⁰+10¹×1¹⁰ < 10⁰+10¹+1¹⁰

Step-by-step explanation:

10⁰×10¹-1¹⁰ = 9

10⁰×10¹×1¹⁰ = 10

10⁰+10¹×1¹⁰ = 11

10⁰+10¹+1¹⁰ = 12

8 0
3 years ago
If you roll 2 dice what are the odds of getting both even numbers
NNADVOKAT [17]
It would be 6 out of 12 chances
4 0
3 years ago
Jonathan, a college business student wants to study how many pages of notes fellow classmates took during a semester for a finan
Naya [18.7K]

Answer:

I just woke up and broke my right knee

8 0
3 years ago
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