1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Zielflug [23.3K]
3 years ago
5

Write 2.5896 * 10^-4 in standard form

Mathematics
1 answer:
7nadin3 [17]3 years ago
4 0

Answer: use a standard form calculator

Step-by-step explanation: it helps alot :)

You might be interested in
Determine the x-intercept of the graph
zhuklara [117]
Answer: the x intercepts at -4 and 4

Why? It’s both because it says intercepts and because they both intercept the x axis
7 0
3 years ago
What is the value of the expression 3x+4 when x=7?
Pani-rosa [81]

Answer: 25

Step-by-step explanation: 7x3 = 21+4 =25

Hope this helped!

Mark Brainliest if you want!

7 0
3 years ago
Read 2 more answers
What is the lcm of 56 and 136
Citrus2011 [14]

Answer:

LCM(56,136)=952

Step-by-step explanation:

To find the LCM of two numbers, factorize both these numbers:

56=2\cdot 28=2\cdot 2\cdot 14=2\cdot 2\cdot 2\cdot 7=2^3\cdot 7\\ \\136=2\cdot 68=2\cdot 2\cdot 34=2\cdot 2\cdot 2\cdot 17=2^3\cdot 17

These two numbers have the common factor of 2^3.

Now multiply this common factor by the remaining factors:

LCM(56,136)=2^3 \cdot 7\cdot 17=952

Therefore, the LCM is 952.

8 0
3 years ago
In ADEF, m must be true?<br> Plssss need helpppp
Rzqust [24]

Answer:

E. FD<DE<EF

Step-by-step explanation:

First I needed to find the other angle which I found by adding the two angles that were given.

103 +14 =117

180 - 117= 63

then to find which sides were the longest I looked and the angles and found their corresponding sides.

<D went with side FE

<F went with side DE

<E went with side FD

The smallest angle was <E therefore the smallest side was FD

The middle angle was <F therefore the medium side was DE

The largest angle was <D therefore the smallest side was FE

I hope this helps!!

Please tell me if I have made a mistake enjoy learning from them!!

If I am correct could you please mark me brainliset? I am trying to level up!!

Thank you for your time:)

5 0
2 years ago
the density of pure gold 1,204 pounds per cubic foot? how many cubic feet is 481.6lbs of pure gold?
Nadusha1986 [10]

Answer:

Volume of Gold = 0.4 cubic feet.

Step-by-step explanation:

First we have to make sure the units are same as the units the answer is required in.

Answer should be given in cubic feet.

Density is given in pounds per cubic foot. And Mass is given in pounds. So units are in order. Therefore, we can go ahead with the calculation.

The Density of Gold = [Mass of Gold/Volume of Gold]

By substituting values,

1204 ponds per cubic foot = [481.6 pounds / Volume of gold]

Making Volume of God the subject of the equation,

Volume of Gold = [481.6 pounds / tex]1204[/tex] ponds per cubic foot ]

Volume of Gold = 0.4 cubic feet.

5 0
3 years ago
Other questions:
  • If cos x cos (pi/7)+sin x sin(pi/7)=-(sqrt 2)/2,then x can equal
    7·1 answer
  • Write a real world situation for the function f(x) = 3(1.06x) + 2. Be sure to identify all key features of the function as what
    5·1 answer
  • Can someone please help me find mDE i will give good rating
    11·1 answer
  • Simplify completely x2 + 4x - 45/x2 +10x+9 and find the restrictions on the variable.
    13·1 answer
  • Plssss helppppppppp 333333333333
    10·1 answer
  • What is the measure of arc FG?<br> PLEASE HELP , i’ll make BRAINLIEST
    6·2 answers
  • 54 + 38<br> -<br> = (52 +<br> D + 38<br> -<br> =52+ (<br> +38)<br> = 52 +<br> II
    14·1 answer
  • Don't spam...<br><br>Step by step explaination needed...​
    11·2 answers
  • MP is the angle bisector of LMN. Given that LMP is a right angle.
    9·1 answer
  • An audiometer is a machine that tests a person’s hearing by producing tones across the speech spectrum. during a hearing test, a
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!