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2 years ago

10

4x-

dle" class="latex-formula"> + 5x

1 answer:

Delvig [45]2 years ago

6 0

The answer most likely is 9

You might be interested in

Match the identities to their values taking these conditions into consideration sinx=sqrt2 /2 cosy=-1/2 angle x is in the first

BaLLatris [955]

Answer:

$\cos(x+y)$ goes with $-\frac{\sqrt{6}+\sqrt{2}}{4}$

$\sin(x+y)$ goes with $\frac{\sqrt{6}-\sqrt{2}}{4}$

$\tan(x+y)$ goes with $\sqrt{3}-2$

Step-by-step explanation:

$\cos(x+y)$

$\cos(x)\cos(y)-\sin(x)\sin(y)$ by the addition identity for cosine.

We are given:

$\sin(x)=\frac{\sqrt{2}}{2}$ which if we look at the unit circle we should see

$\cos(x)=\frac{\sqrt{2}}{2}$ .

We are also given:

$\cos(y)=\frac{-1}{2}$ which if we look the unit circle we should see

$\sin(y)=\frac{\sqrt{3}}{2}$ .

Apply both of these given to:

$\cos(x+y)$

$\cos(x)\cos(y)-\sin(x)\sin(y)$ by the addition identity for cosine.

$\frac{\sqrt{2}}{2}\frac{-1}{2}-\frac{\sqrt{2}}{2}\frac{\sqrt{3}}{2}$

$\frac{-\sqrt{2}}{4}-\frac{\sqrt{6}}{4}$

$\frac{-\sqrt{2}-\sqrt{6}}{4}$

$-\frac{\sqrt{6}+\sqrt{2}}{4}$

Apply both of the givens to:

$\sin(x+y)$

$\sin(x)\cos(y)+\sin(y)\cos(x)$ by addition identity for sine.

$\frac{\sqrt{2}}{2}\frac{-1}{2}+\frac{\sqrt{3}}{2}\frac{\sqrt{2}}{2}$

$\frac{-\sqrt{2}+\sqrt{6}}{4}$

$\frac{\sqrt{6}-\sqrt{2}}{4}$

Now I'm going to apply what 2 things we got previously to:

$\tan(x+y)$

$\frac{\sin(x+y)}{\cos(x+y)}$ by quotient identity for tangent

$\frac{\sqrt{6}-\sqrt{2}}{-(\sqrt{6}+\sqrt{2})}$

$-\frac{\sqrt{6}-\sqrt{2}}{\sqrt{6}+\sqrt{2}}$

Multiply top and bottom by bottom's conjugate.

When you multiply conjugates you just have to multiply first and last.

That is if you have something like (a-b)(a+b) then this is equal to a^2-b^2.

$-\frac{\sqrt{6}-\sqrt{2}}{\sqrt{6}+\sqrt{2}} \cdot \frac{\sqrt{6}-\sqrt{2}}{\sqrt{6}-\sqrt{2}}$

$-\frac{6-\sqrt{2}\sqrt{6}-\sqrt{2}\sqrt{6}+2}{6-2}$

$-\frac{8-2\sqrt{12}}{4}$

There is a perfect square in 12, 4.

$-\frac{8-2\sqrt{4}\sqrt{3}}{4}$

$-\frac{8-2(2)\sqrt{3}}{4}$

$-\frac{8-4\sqrt{3}}{4}$

Divide top and bottom by 4 to reduce fraction:

$-\frac{2-\sqrt{3}}{1}$

$-(2-\sqrt{3})$

Distribute:

$\sqrt{3}-2$

6 0

2 years ago

Helpppppppppppppppppppppppppppppppppppppp

Dmitry_Shevchenko [17]

Answer: 403

find the absolute value of -272, which is 272.

add 272 to the 131

that equals the height of 403 ft

4 0

2 years ago

Read 2 more answers

Help me!!! Please and thank you!!!

Novay_Z [31]

Answer:

Third option is correct: 1 / (t+4)^2

Step-by-step explanation:

This equation can be written as the following:

(t+3)/(t+4)*(1/t^2+7t+12)

We know this because of the division of fractions. For example:

(1/y)/(1/x) = (1/y)*(x/1)

Now that we know this, we can advance.

Now we have to try to factor (t^2+7t+12)

We can make this into (t+3)(t+4)

Ah! Perfect! There is a t+3 in the denominator of the first fraction!

We can now cancel these out.

Now our equation looks like this:

(1 / t+4) * (1 / t+4)

This can also be written as 1^2 / (t+4)^2 = 1 / (t+4) ^2

So the correct option is the third one.

6 0

3 years ago

Water weighs about 8.34 pounds per gallon. About how many ounces per gallon is the weight of the water?

NeX [460]

There are 16 ounces per pound so 16 x 8 is154 ounces then about 4 more ounces to get the .34 so in total 158 fl ounces∀

7 0

3 years ago

Ben has 9 trading cards. Tyler has 36 trading cards, which is 4 times as many trading cards as Ben.

nalin [4]

Answer: I would need a picture of the exact set up of the question but I think it would go.

T=4b

B= 9

Step-by-step explanation:

6 0

2 years ago