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Leni [432]
2 years ago
7

In order to earn the money to buy a car, you will need to start a job. You have two options and should decide which job to take.

Mathematics
1 answer:
kipiarov [429]2 years ago
8 0

If I can work 15 hours, I would make more money at the restaurant.

If I can work more hours, I would make more money at my dad's office.

The job I would choose is the job at my dad's office. This is because I would earn more money at this job.

<h3>Amount earned at the dad's office</h3>

The amount of money I would earn at my dad's office can be determined by multiplying the pay per hour by the total number of hours I work.

Amount that would be earned at my dad's office = fixed earnings + variable earnings

$10 + ( $8 x 15) = $130.

<h3 /><h3>Amount earned at the restaurant</h3>

The amount of money I would earn at the restaurant, can be represented with this equation: ($5.50 x 15) + [0.6 x ($5.50 x 15)]

$82.50 + $49.50 = $132

<h3>Amount earned if I work extra hours</h3>

Amount I would earn  at my dad's office if I work for 20 hours = (20 x $8) + $10 = $170

The amount of money I would earn at the restaurant if I work for 18 hours = ($5.50 x 18) + [0.6 x ($5.50 x 18)]

= $99 + $59.40 = $158.40

To learn more about how to determine total earnings, please check: brainly.com/question/8605

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There would be no pennies
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3 years ago
An insect is 3.5 millimeters long. Which expression finds the length of the insect in decimeters? Use the metric table to help a
rewona [7]

Answer:

The length of the insect in decimeters is: 0.035 decimeters

Step-by-step explanation:

The metric table help us to know:

1 decimeter =100 millimeters

To answer the question we need to know how many decimeters are 3.5 millimeters, so:

3.5 millimeters*\frac{1 decimeter}{100 millimeters}= 0.035 decimeters

The length of the insect in decimeters is: 0.035 decimeters

6 0
3 years ago
Read 2 more answers
The article "Occurrence and Distribution of Ammonium in Iowa Groundwater" (K. Schilling, Water Environment Research, 2002:177–18
Papessa [141]

Answer: 95% confidence interval for the difference between the proportions would be (1.31, 1.39).

Step-by-step explanation:

Since we have given that

Number of alluvial wells = 349

Number of quaternary wells = 143

Number of alluvial wells that had concentrations above 0.1 = 182

Number of quaternary wells that had concentrations above 0.1 = 112

Average of alluvial wells = 0.27

Standard deviation = 0.4

Average of quaternary wells = 1.62

Standard deviation =1.70

So, 95% confidence interval gives

alpha = 5% level of significance.

\dfrac{\alpha}{2}=2.5\%\\\\z_{\frac{\alpha}{2}}=1.96

So, 95% confidence interval becomes,

(1.62-0.27)\pm 1.96\sqrt{\dfrac{0.4^2}{349}+\dfrac{1.7^2}{143}}\\\\=1.35\pm 1.96\times 0.020\\\\=(1.35-0.040,1.35+0.040)\\\\=(1.31,1.39)

Hence, 95% confidence interval for the difference between the proportions would be (1.31, 1.39).

6 0
3 years ago
Complete the sentence below. A function f is​ _____ on an open interval I​ if, for any choice of x1 and x2 in​ I, with x1less th
mojhsa [17]

Answer:

Increasing if f' >0 and decreasing if f'<0

Step-by-step explanation:

Difference quotient got by getting

\frac{f(x+h)-f(x)}{h} will be greater than 0 if function is increasing otherwise negative

Here h is a small positive value.

In other words, we find that whenever first derivative of a function f(x) is positive the function is increasing.

Here given that for x1, x2 where x1<x2, we have

if f(x1) <f(x2) then the function is decreasing.

Or if x1<x2 and if f(x1) >f(x2) for all x1, and x2 in I the open interval we say f(x) is decreasing in I.

5 0
3 years ago
The room shown below right is 14 ft by 10 ft. Find the dimensions of each piece of furniture to the nearest tenth . 16))
DENIUS [597]

Answer:

Follows are the solution to this question:

Step-by-step explanation:

Please find the image file of the question:

The dresser dimension is:

L= 6.0 \ feet\\\\ W= 3.0 \ feet

The bed dimension is:

L = 7.1\  feet\\\\W = 5.7\  feet

 The table dimension is:

L = 2.8 \ feet\\\\W= 2.8 \ feet

6 0
3 years ago
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