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3 years ago

14

a patrolman gives a speeding ticket 15% over the posted speed the speed limit is 40 miles per hour a driver can go without recei

ving a ticket

1 answer:

Alexus [3.1K]3 years ago

5 0

0.15 x 40 = 6 and 40+6 = 46
So you can drive below 46 miles per hour without getting a ticket
Hope this helps!

You might be interested in

Solve for x: 1-2(x+1) = x+6

brilliants [131]

Answer:

Exact Form: x= - 7/3

Hope this helped! If you ever need anymore help feel free to ask. :)

4 0

3 years ago

HELP!!! I WILL GIVE BRAINLIEST!!! 10 PTS!!!

tatiyna

Answer:

x= 55 degrees

w = 5

Step-by-step explanation:

Triangle PQR contains two triangles, QPS and PSR.

Looking at triangle QPS, it is an isosceles triangle. This is shown by the two short lines that cuts line QP and line QS.

In an isosceles triangle, two sides and two angles are equal. The two equal angles are the base angles.

Therefore,

angle P and angle S are equal. Also

Line QP and line PS are equal. This means

6w - 10 = w

6w-w = 10

5w = 10

w = 10/2 = 5

Angle Q + 100 degrees = 180 ( sum of angles on a straight line)

Angle Q = 180 - 100 = 80 degrees

Angle Q = Angle S(base angles of an isosceles triangle)

Angle PSR = 180 - 80 = 100 degrees( sum of angles on a straight line is 180)

Angle PSR + x + 25 = 180

x = 180 - 25 - 100 = 55 degrees

6 0

3 years ago

Convert 4 gallons to pints. Choose the words and numbers to complete the statements. A gallon is a unit than a pint. the number

Troyanec [42]

Answer:

The answer is 32 pints

5 0

4 years ago

3. West deposited $15,500 in a savings account earning 2.5% interest. What was the total interest earned at the end of 8 years?

Hunter-Best [27]

<span>$15,500 + 0.025 * 8 = $3,100

answer is </span><span>C. $3,100.00</span>

7 0

4 years ago

4. Using the geometric sum formulas, evaluate each of the following sums and express your answer in Cartesian form.

nikitadnepr [17]

Answer:

$\sum_{n=0}^9cos(\frac{\pi n}{2})=1$

$\sum_{k=0}^{N-1}e^{\frac{i2\pi kk}{2}}=0$

$\sum_{n=0}^\infty (\frac{1}{2})^n cos(\frac{\pi n}{2})=\frac{1}{2}$

Step-by-step explanation:

$\sum_{n=0}^9cos(\frac{\pi n}{2})=\frac{1}{2}(\sum_{n=0}^9 (e^{\frac{i\pi n}{2}}+ e^{\frac{i\pi n}{2}}))$

$=\frac{1}{2}(\frac{1-e^{\frac{10i\pi}{2}}}{1-e^{\frac{i\pi}{2}}}+\frac{1-e^{-\frac{10i\pi}{2}}}{1-e^{-\frac{i\pi}{2}}})$

$=\frac{1}{2}(\frac{1+1}{1-i}+\frac{1+1}{1+i})=1$

2nd

$\sum_{k=0}^{N-1}e^{\frac{i2\pi kk}{2}}=\frac{1-e^{\frac{i2\pi N}{N}}}{1-e^{\frac{i2\pi}{N}}}$

$=\frac{1-1}{1-e^{\frac{i2\pi}{N}}}=0$

3th

$\sum_{n=0}^\infty (\frac{1}{2})^n cos(\frac{\pi n}{2})==\frac{1}{2}(\sum_{n=0}^\infty ((\frac{e^{\frac{i\pi n}{2}}}{2})^n+ (\frac{e^{-\frac{i\pi n}{2}}}{2})^n))$

$=\frac{1}{2}(\frac{1-0}{1-i}+\frac{1-0}{1+i})=\frac{1}{2}$

What we use?

We use that

$e^{i\pi n}=cos(\pi n)+i sin(\pi n)$

and

$\sum_{n=0}^k r^k=\frac{1-r^{k+1}}{1-r}$

6 0

4 years ago