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3 years ago

5

1) While your family is visiting Deep Creek Lake, you and your brother decide to go boating. The

1 answer:

notsponge [240]3 years ago

8 0

Answer:

Y=10x+25

Step-by-step explanation:

Hey so let’s take the number of hours we go boating as “x” and the TOTAL cost of this whole trip as “y”.

So obviously y would equal everything else so we can write

Y=

Next, it says we rent a canoe for $10 an hour. That means we would have to multiply 10 and x to find the cost of the rent.

So

Y=10x

Finally, it says we paid a registration fee of $25. This 25 is not affected by the number of hours or anything else. It is a fixed amount so we can represent it as

Y=10x+25

Hope this helps!

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The hawaiian language has 12 letters: five vowels and seven consonants. each of the 12 hawaiian letters are written on a slip of

miskamm [114]

1. There are12 total letters 5 vowels and 7 consonants in the hawaiin alphabet.

2. probability of 1st letter being a vowel is 5/12
3. probability of 2nd letter being a vowel is 5/12
4. probability of both occurring is (5/12 * 5/12) = 25/144 ←

5 0

3 years ago

Read 2 more answers

Please please help will give brainlist

Alla [95]

Step-by-step explanation:

$13 \frac{1}{8}$

is the required answer

3 0

2 years ago

Pls<br> Help me <br> I need it

ad-work [718]

Answer:

${2}^{7}$

Step-by-step explanation:

${2}^{7} = 128$

${7}^{2} = 49$

So,

$128 > 49 \\ {2}^{7} \: \: \: \: > {7}^{2}$

Therefore 2^7 is greater

4 0

3 years ago

Find a polynomial with integer coefficients that satisfies the given conditions. R has degree 4 and zeros 3 − 3i and 2, with 2 a

dolphi86 [110]

Answer:

The required polynomial is $P(x)=x^4-10x^3+46x^2-96x+72$ .

Step-by-step explanation:

If a polynomial has degree n and $c_1,c_2,...,c_n$ are zeroes of the polynomial, then the polynomial is defined as

$P(x)=a(x-c_1)(x-c_2)...(x-x_n)$

It is given that the polynomial R has degree 4 and zeros 3 − 3i and 2. The multiplicity of zero 2 is 2.

According to complex conjugate theorem, if a+ib is zero of a polynomial, then its conjugate a-ib is also a zero of that polynomial.

Since 3-3i is zero, therefore 3+3i is also a zero.

Total zeroes of the polynomial are 4, i.e., 3-3i, 3_3i, 2,2. Let a=1, So, the required polynomial is

$R(x)=(x-3+3i)(x-3-3i)(x-2)(x-2)$

$R(x)=((x-3)+3i)((x-3)-3i)(x-2)^2$

$R(x)=(x-3)^2-(3i)^2((x-3)-3i)(x-2)^2$ $[a^2-b^2=(a-b)(a+b)]$

$R(x)=(x^2-6x+9-9(i)^2((x-3)-3i)(x-2)^2$

$R(x)=(x^2-6x+18)(x^2-4x+4)$ $[i^2=-1]$

$R(x)=(x^2-6x+18)(x^2-4x+4)$

$R(x)=x^4-10x^3+46x^2-96x+72$

Therefore the required polynomial is $P(x)=x^4-10x^3+46x^2-96x+72$ .

3 0

3 years ago

Radioactive Decay Beginning with 16 grams of a radioactive element whose half -life is 30 years ,the mass y(in grams) remaining

Flura [38]

Answer:

the equation should be corrected to fit the data of the problem. With the corrected equation a mass of 0.5 grams remains after 150 years

Step-by-step explanation:

for the mass y( in grams)

y=23* (1/2)^(t/45), t ≥ 0.

the initial mass is at t=0 , then

y= 23 grams → should be 16 grams

half-life from the equation = 45 years → should be 30 years

the correct equation should be

y=16*(1/2)^(t/30), t ≥ 0

then after 150 years → t= 150

y=16*(1/2)^(150/30)= 16*(1/2)^5 = 16/32 = 0.5 grams

then a mass of 0.5 grams remains after 150 years

5 0

3 years ago