Answer:
The weight of the brick is 60 ounce to the nearest ounce
Step-by-step explanation:
In this question, we are asked to calculate the weigh of Lou’s brick given the dimensions of the shape of the brick and the weight of the clay.
To answer this question quite aptly, we need to know exactly the volume of the rectangular prism given the dimensions we have in the question.
To calculate this volume , we simply use the measurements we have to get it.
mathematically the volume of a rectangular prism is simply V = w * h * l
where w , h and l are width, height and length respectively.
now let’s calculate!
V = 3.5 * 2.25 * 8 = 63 inches^3
Now we need to know what the brick weigh in ounce. We already have the weight of the clay. now this is equal to the volume of the brick divided by the weight of the clay.
Mathematically this is = 63/1.055 = 59.72 ounce which is 60 ounce to the nearest ounce
How do I convert these improper fractions to mixed numbers: 29/4, 13/6, 73/9, 65/8, 17/2, 5/2, 25/4, 43/7, 29/4, 73/9, 19/3, 43/
slava [35]
Divide the numerator by the denominator
use the answer as the whole number
use the remainder as the numerator
keep the deniminator
the answers:
7 1/4
2 1/6
8 1/8
8 1/2
2 1/2
6 1/4
6 1/7
7 1/4 (same question)
8 1/8 (same question)
6 1/3
2 1/5
9 1/10
6 1/6
Answer:
![a)\ \ \bar x_m-\bar x_f=67.03\\\\b)\ \ E=15.7416\\\\c)\ \ CI=[51.2884, \ 82.7716]](https://tex.z-dn.net/?f=a%29%5C%20%5C%20%5Cbar%20x_m-%5Cbar%20x_f%3D67.03%5C%5C%5C%5Cb%29%5C%20%5C%20E%3D15.7416%5C%5C%5C%5Cc%29%5C%20%5C%20CI%3D%5B51.2884%2C%20%5C%2082.7716%5D)
Step-by-step explanation:
a. -Given that:
#The point estimator of the difference between the population mean expenditure for males and the population mean expenditure for females is calculated as:
Hence, the pointer is estimator 67.03
b. The standard error of the point estimator,
is calculated by the following following:
-And the margin of error, E at a 99% confidence can be calculated as:
Hence, the margin of error is 15.7416
c. The estimator confidence interval is calculated using the following formula:
#We substitute to solve for the confidence interval using the standard deviation and sample size values in a above:
![CI=\bar x_m-\bar x_f\ \pm z_{\alpha/2}\sqrt{\frac{\sigma_m^2}{n_m}+\frac{\sigma_f^2}{n_f}}\\\\=(135.67-68.64)\pm 15.7416\\\\=67.03\pm 15.7416\\\\=[51.2884, \ 82.7716]](https://tex.z-dn.net/?f=CI%3D%5Cbar%20x_m-%5Cbar%20x_f%5C%20%5Cpm%20z_%7B%5Calpha%2F2%7D%5Csqrt%7B%5Cfrac%7B%5Csigma_m%5E2%7D%7Bn_m%7D%2B%5Cfrac%7B%5Csigma_f%5E2%7D%7Bn_f%7D%7D%5C%5C%5C%5C%3D%28135.67-68.64%29%5Cpm%2015.7416%5C%5C%5C%5C%3D67.03%5Cpm%2015.7416%5C%5C%5C%5C%3D%5B51.2884%2C%20%5C%2082.7716%5D)
Hence, the 99% confidence interval is [51.2884,82.7716]
The radius of a circle is half the diameter.
Thus, the radius (r) is >>>
The area of a circle is given by the formula,
Where
r is the radius
Substituting the radius value into the area formula, we have:
