All categories

3 years ago

If g(x) = 2x - 5 and h(x) = 3x + 7, then g(h(x)) = ?

Mathematics

1 answer:

lana [24]3 years ago

8 0

Step-by-step explanation:

$g(x) = 2x - 5$

$h(x) = 3x + 7$

To determine $g(h(x))$ , wherever you see an $x$ in $g(x)$ , replace it with the equation $h(x)$ :

$g(x) = 2x - 5$

$g(h(x)) = 2(h(x)) - 5$

$g(h(x)) = 2(3x + 7) - 5$

$g(h(x)) = 6x + 14 - 5$

$g(h(x)) = 6x + 9$

You might be interested in

Pay the bill using the fewest possible bills/coins

marysya [2.9K]

Answers:

Open the pdf below and youll find what you need. also do the largest bills you can.

Download pdf

4 0

3 years ago

What is the answer to this 19 3/4 / 2

Svet_ta [14]

Answer:

79/8

Step-by-step explanation:

19 3/4 = 79/4

79/4 / 2 is same as 79/4 * 1/2

79/8

Answer: 79/8

6 0

3 years ago

Read 2 more answers

Write a numerical expression for the verbal expression. the sum of two an four and six times eight

Trava [24]

(2+4+6)*8 hopefully that's what you are looking for

3 0

3 years ago

Use the relationships in the diagram to find the value of C<br> 520<br> d<br> 379<br> 63

Brut [27]

Answer:

c = 154°

Step-by-step explanation:

I Hope this helps.

7 0

3 years ago

a port and a radar station are 2 mi apart on a straight shore running east and west. a ship leaves the port at noon traveling no

Rom4ik [11]

Answer:

The rate of change of the tracking angle is 0.05599 rad/sec

Step-by-step explanation:

Here the ship is traveling at 15 mi/hr north east and

Port to Radar station = 2 miles

Distance traveled by the ship in 30 minutes = 0.5 * 15 = 7.5 miles

Therefore the ship, port and radar makes a triangle with sides

2, 7.5 and x

The value of x is gotten from cosine rule as follows

x² = 2² + 7.5² - 2*2*7.5*cos(45) = 39.04

x = 6.25 miles

By sine rule we have

$\frac{sin A}{a} = \frac{sin B}{b}$

Therefore,

$\frac{sin 45}{6.25} = \frac{sin \alpha }{7.5}$

α = Angle between radar and ship α

∴ α = 58.052

Where we put

$\frac{sin 45}{6.25} = \frac{sin \alpha }{x}$ to get

$\frac{x}{6.25} = \frac{sin \alpha }{sin 45}$ and differentiate to get

$\frac{\frac{dx}{dt} }{6.25} = cos\alpha\frac{\frac{d\alpha }{dt} }{sin 45}$

$\frac{15sin45 }{6.25cos\alpha } =\frac{d\alpha }{dt} }$ = 3.208 degrees/second = 0.05599 rad/sec.

6 0

3 years ago