<span>To produce 1000L of mixture the factory will need 657 liters of grade A and 343 liters of grade B. To determine this you have to figure out the percentage of each grade in the mixture. The ratio is 2.3 liters to 1.2 liters. Therefor in this scenario the unit equaling 100% is 3.5 liters. To find the percentage of grade A you divide the amount used by the total amount of the unit 100%:
2.3 divided by 3.5 = .657 (multiply the answer by 100 to get 65.7%).
To find the percentage of grade B you divide the amount used by the total amount of the unit 100%:
1.2 divided by 3.5 = .343 (multiply the answer by 100 to get 34.3%)
To test your answer make sure both percentages add up to 100%:
65.75 plus 34.35 = 100%
To determine how much of grade A and grade B is needed for a set amount of liters you multiply the percentage by the liters needed.
For this situation you multiply 65.7% (when multiplying percentages you need to multiply in decimal form).
For grade A you multiply .657 (65.7%) by 1000 liters = 657 liters
For grade B you multiply .343 (34.3%) by 1000 liters = 343 liters
To test your answer you can use the same addition as you did to test the percentages:
657 liters plus 343 liters = 1000 liters</span>
Answer:
0.16
Step-by-step explanation:
For a normal distribution, the 68-95-99.7 rule says that 68% of the distribution lies within 1 standard deviation from the mean, 95% within two standard deviations and 99.7% within three standard deviations.
From the question,
Mean μ = 298 ml
Standard deviation σ = 3 ml
A value of 295 ml is within one standard deviation = 68%.
Since it's on the lower side, it's within 68% ÷ 2 = 34%.
The lower half below the mean is 50% of the distribution. Hence, for a selection less than 1 standard deviation, the probability is
50% - 34% = 16% = 0.16
Answer: C
Step-by-step explanation:
y2-y1/x2-x1
-9+7/5-6 = 2
1) x = - 4, y = - 12; (- 4, - 12)
2) x = 34, y = 17; (34, 17)
3) x = 16, y = 7; (16, 7)
4) x = 7, y = - 4; (7, - 4)
5) x = - 4, y = 10; (- 4, 10)
6) x = 12, y = - 7; (12, - 7)
7) x = 5, y = 10; (5, 10)
8) x = 11, y = - 12; (11, - 12)
