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lara31 [8.8K]
3 years ago
7

What is the constant of proportionality in the equation x/y = 2/g?

Mathematics
1 answer:
LenKa [72]3 years ago
6 0

Answer:

2

Step-by-step explanation:

The constant of proportionality in the equation x/y = 2/g is 2. 2 is the only number in the equation.

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In total there is 3000 millileters
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Write the following equation in the general form Ax+ By+ C:
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Find the absolute minimum and absolute maximum values of f on the given interval. f(t) = 3 (*sqaure root sign*) t (20 − t), [0,
mafiozo [28]

9514 1404 393

Answer:

  • maximum: 15∛5 ≈ 25.6496392002
  • minimum: 0

Step-by-step explanation:

The minimum will be found at the ends of the interval, where f(t) = 0.

The maximum is found in the middle of the interval, where f'(t) = 0.

  f(t)=\sqrt[3]{t}(20-t)\\\\f'(t)=\dfrac{20-t}{3\sqrt[3]{t^2}}-\sqrt[3]{t}=\sqrt[3]{t}\left(\dfrac{4(5-t)}{3t}\right)

This derivative is zero when the numerator is zero, at t=5. The function is a maximum at that point. The value there is ...

  f(5) = (∛5)(20-5) = 15∛5

The absolute maximum on the interval is 15∛5 at t=5.

5 0
2 years ago
Which situation is most likely to have a constant rate of change? A. Length of a bead necklace compared with the number of ident
Kipish [7]

Answer:

A. Length of a bead necklace compared with the number of identical beads

Step-by-step explanation:

Using identical beads in a necklace means that the length of the necklace will depend on the total number of identical beads in the necklace.

For each bead added, the length of the necklace will increase a given, constant, amount.  This is a constant rate of change.

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System of Equations <br> Need help<br> Trig
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Looks like the system is

\begin{cases}-2x+y+6z=1\\3x+2y+5z=16\\7x+3y-4z=11\end{cases}

We can eliminate y by taking

(3x+2y+5z)-2(-2x+y+6z)=16-2(1)

\implies3x+2y+5z+4x-2y-12z=16-2

\implies7x-7z=14

\implies x-z=2

so that z=x-2, and

(7x+3y-4z)-3(-2x+y+6z)=11-3(1)

\implies7x+3y-4z+6x-3y-18z=11-3

\implies13x-22z=8

Substitute z=x-2 into this last equation and solve for x:

13x-22(x-2)=8

\implies13x-22x+44=8

\implies-9x=-36

\implies x=4

Then

z=x-2

\implies z=4-2

\implies z=2

Plug these values into any one of the original equation to solve for y:

-2x+y+6z=1

\implies-2(4)+y+6(2)=1

\implies-8+y+12=1

\implies y=-3

Hence the solution is x = 4, y = -3, and z = 2.

6 0
3 years ago
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