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natulia [17]
1 year ago
9

The midpoint of AB is M (4, 4). If the coordinates of A are (2, 1), what are the

Mathematics
1 answer:
Sergio [31]1 year ago
7 0

Answer:

(6,7)

Step-by-step explanation:

Let B(x,y).

By the midpoint formula,

  • 4 is the average of 2 and x, so x = 6.
  • Similarly, y = 7.

So, the coordinates of B are (6,7).

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What is the product of all constants $k$ such that the quadratic $x^2 + kx +15$ can be factored in the form $(x+a)(x+b)$, where
Setler79 [48]

Answer:

k=-16,k=-8,k=8,k=16

Step-by-step explanation:

We are given quadratic equations as

x^2+kx+15

and it can be factored as

=(x+a)(x+b)

now, we can multiply factor term

(x+a)(x+b)=x^2+(a+b)x+ab

now, we can compare

x^2+(a+b)x+ab=x^2+kx+15

so, we get

k=a+b

ab=15

we are given that

'a' and 'b' are integers

so, we can find all possible factors

15=(-1\times -15),(1\times 15)

15=(-3\times -5),(3\times 5)

so, we can find k

At (-1\times -15):

k=a+b

we can plug values

k=-1-15

k=-16

At (1\times 15):

k=a+b

we can plug values

k=1+15

k=16

At (-3\times -5):

k=a+b

we can plug values

k=-3-5

k=-8

At (3\times 5):

k=a+b

we can plug values

k=3+5

k=8

So, values of k are

k=-16,k=-8,k=8,k=16

6 0
3 years ago
The radius of Circle A is 6 mm. The radius of Circle B is 4 mm greater than the radius of Circle A. The radius of Circle C is 2
labwork [276]

Answer:

Area of circle A =113.14 mm²

Area of circle b = 314.29 mm²

Area of circle C = 452.57 mm²

Area of circle A = 254.57 mm²

2.25 times

Step-by-step explanation:

Area of a circle = nr²

where n = 22/7

r = radius

Circle A's radius = 6mm

Circle B's radius = 6mm + 4mm = 10mm

Circle C's radius = 10mm + 2mm = 12mm

Circle D's radius = 12mm - 3mm = 9mm

Area of circle A = (22/7) x 6² = 113.14 mm²

Area of circle b = (22/7) x 10² = 314.29 mm²

Area of circle C = (22/7) x 12² = 452.57 mm²

Area of circle A = (22/7) x 9² = 254.57 mm²

Number of times the area of circle D is greater than that circle A = Area of circle D / Area of circle A

254.57 mm² / 113.14 mm² = 2.25 times

4 0
3 years ago
Tell whether the given value is a solution of the inequality. (yes or no)<br><br> -2 ≤ k/3; k = -9
olga55 [171]

Answer:  No, it is not a solution

Work Shown:

-2 ≤ k/3

-2 ≤ -9/3

-2 ≤ -3

The last inequality is false because -3 should be smaller than -2 (not the other way around). Use a number line to help see this.

Since the last inequality is false, the original inequality must also be false for that particular k value. Therefore, k = -9 is not a solution.

4 0
2 years ago
Please help me out with this quiz! Alegbra One
Taya2010 [7]

Answer:

1B

2A

3C

4C

5C

6A

7A

8D

9B

10C

6 0
3 years ago
Find the real and/or imaginary solutions by factoring
SIZIF [17.4K]

Answer:


Step-by-step explanation:

1) (x-3),(x-8)

2) 3x^3+3x^2=27x

3 ( x 3^3+ x ^2 − 9 x − 9 )

3 ( x ^2 ( x + 1 ) − 9 ( x + 1 ) )

3 ( ( x + 1)( x ^2 − 9 ) )

3 ( ( x + 1 ) ( x ^2 − 3 ^2 ) )

3 ( x + 1 ) ( x + 3 ) ( x − 3 )

6 0
3 years ago
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