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cupoosta [38]
3 years ago
15

A rectagle has a height of 5x and a width of x+2area=???​

Mathematics
1 answer:
astra-53 [7]3 years ago
5 0

Answer: Area=5x^2+10x

Step-by-step explanation:

The area of a rectangle:

a=h×w

a=5x(x+2)

a=5x × x+5x × 2

a=5x^2+10x

-Result:

a=5x^2+10x

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X + 5y - 10 = 0<br> x = 2y - 8
ipn [44]
So since we know what x is, we can substitute it into the original equation for x like so to solve for y...

(2y - 8) + 5y - 10 = 0
2y - 8 + 5y = 10
2y + 5y = 18
7y = 18
y = 18/7 (or about 2.57)

So now we know what x is, we can sub it into the below equation to solve for x...

x = 2(18/7) - 8
x = 36/14 - 8 (or about -5.43)


3 0
3 years ago
HELP PLEASE OR GET YEETED
soldier1979 [14.2K]

Answer:

they never intersect

Step-by-step explanation:

parallel lines are basically two lines that are always the same distance apart and traveling in the same direction at each other.

7 0
2 years ago
Read 2 more answers
What is the equation of the line that passes through the point (-1,7) and is parallel to the line y= -2x-1
Nuetrik [128]

if we look at the equation y = -2x - 1, is already in slope-intercept form, therefore, \bf y=\stackrel{slope}{-2}x-1 has a slope of -2.


now, parallel lines have exactly equal slopes, therefore a parallel to that one above, will have also a slope of -2, so we're really looking for a line whose slope is -2 and runs through -1, 7.


\bf (\stackrel{x_1}{-1}~,~\stackrel{y_1}{7})\qquad \qquad \qquad slope =  m\implies -2\\\\\\\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-7=-2[x-(-1)]\\\\\\y-7=-2(x+1)\implies y-7=-2x-2\implies y=-2x+5

3 0
3 years ago
Find the radius of the circle with a diameter of 100 meters.
Ganezh [65]

Answer:

50

Step-by-step explanation:

100/2

3 0
3 years ago
Read 2 more answers
1 It takes 1 cups of sugar and 3 cups of flour
scZoUnD [109]

For every 1 cup of sugar there's 3 cups of flour or vice versa. (For every 3 cups of flour there's 1 cup of sugar.)

<h2>Answer:</h2>

<u>The ratio of sugar to flour is </u><u>1 to 3</u><u>, </u><u>1:3</u><u>, or </u><u>1/3</u><u>.</u>  (Option B)

Hope this helps :)

8 0
3 years ago
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