What is the slope of this table х у 0 1 1 4 2 4 7 13 16

Mathematics

1 answer:

Jobisdone [24]3 years ago

5 0

Answer:

THE ANSWER IS 222

Step-by-step explanation:

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Which of the following functions are solutions of the differential equation y'' + y = 3 sin x? (select all that apply)

DiKsa [7]

Answer:

Step-by-step explanation:

We must compute the derivatives and check if the equation is satisfied.

A. $y'=(3\sin x)'=3\cos x$ . Differentiate again to get $y''=(3\cos x)'=-3\sin x$ , then $y''+y=-3\sin x+3\sin x=0\neq 3\sin x$ so this choice of y doesn't solve the equation.

B. $y'=3\sin x+3x\cos x-5\cosx +5x\sin x=(5x+3)\sin x+(3x-5)\cos x$ and $y''=5\sin x+(5x+3)\cos x+3\cos x-(3x-5)\sin x=(10-3x)\sin x+(5x+6)\cos x$ , then $y''+y=10\sin x+6\cos x\neq 3\sin x$ so y is not a solution

C. $y'=\frac{-3}{2}\cos x+\frac{3}{2}x\sin x$ hence $y''=\frac{3}{2}\sin x+\frac{3}{2}\sin x+\frac{3}{2}x\cos x=3\sin x+\frac{3}{2}x\cos x$ . Then $y''+y=3\sin x+\frac{3}{2}x\cos x-\frac{3}{2}x\cos x=3\sin x$ so y is a solution.

D. $y'=-3\sin x$ and $y''=-3\cos x$ , then $y''+y=0$ thus y isn't a solution

E. $y'=\frac{3}{2}\sin x+\frac{3}{2}x\cos x$ hence $y''=\frac{3}{2}\cos x+\frac{3}{2}\cos x-\frac{3}{2}x\sin x=3\cos x-\frac{3}{2}x\cos x$ . Then $y''+y=3\cos x-\frac{3}{2}x\cos x-\frac{3}{2}x\cos x=3\cos x\neq 3\sin x$ then y is not a solution.

3 0

3 years ago

2y - A / 3 equals a + 3 B / 4 solving for y

melamori03 [73]

To solve for y you need to first multiply both sides by 4. This will give you: 4y - 4A / 3 = A + 3B

Next you need to multiply both sides by 3: 4y - 4A = 3A + 9B

Now you need to add 4A to both sides: 4y = 7A + 9B

Now divide both sides by 4:

Y = 7A/4 + 9B/4

8 0

3 years ago

If 37 represents an increase of 37, what does -37 represents

Genrish500 [490]

Probs a decrease of 37 boiiii

5 0

4 years ago

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How many perfect cubes are there between 2 to 200 ?<br> ANSWER fast

Mekhanik [1.2K]

Answer:

Three