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4 years ago

7

NEED HELP ASAP PLEASE AND THANK YOU ALEGRA 1

2 answers:

sammy [17]4 years ago

5 0

16 and 157
Accordingly

fenix001 [56]4 years ago

5 0

I hope this helps you

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A restaurant charges $3 for a soda and it includes free unlimited

worty [1.4K]

The answer is zero
For each soda you would be the price would go up
The slope is that price that you buy the soda
Except since it is unlimited it means we don’t have to pay for the soda each time we buy one
So every time we buy a soda the price we pay for is not existent
I hope this helps

5 0

3 years ago

Solve for w. w/4 -5 = 4

GuDViN [60]

W/4-5=4
w/-1=4
write it so that the w is fractioned over the -1
w=-4

7 0

4 years ago

Read 2 more answers

Devon is trying to find the unit price on a 6-pack of drinks on sale for $2.99. His sister says that at that price, each drink w

Julli [10]

No, she's no good at math...

2.99/6 = about fifty cents a drink.

7 0

3 years ago

Let m(x) = x / x−1

allsm [11]

Answer with Step-by-step explanation:

We are given that a function

$m(x)=\frac{x}{x-1}$

a.We have to find the inverse of m.

Suppose, $y=m(x)=\frac{x}{x-1}$

$yx-y=x$

$yx-x=y$

$x(y-1)=y$

$x=\frac{y}{y-1}$

Replace x by y and y by x

$y=\frac{x}{x-1}$

Substitute $y=m^{-1}(x)$

$g(x)=m^{-1}(x)=\frac{x}{x-1}$

b.When the inverse function of given function is $\frac{x}{x-1}$

Then , we get fog(x)= $f(g(x))=\frac{\frac{x}{x-1}}{\frac{x}{x-1}-1}$

$fog(x)=\frac{x}{x-x+1}=x=I(x)$

When f and g are inverse to each other then fog(x)=Identity function.

c.If f(x)=x

It is self inverse function.

8 0

4 years ago

A new fertilizer was applied to the soil of 146 bean plants. 23% showed increased growth. Find the margin of error and 95% confi

USPshnik [31]

Answer:

The significance level for this case would be $\alpha=1-0.95=0.05$ and the critical value for this case would be:

$z_{\alpha/2}=1.96$

The margin of error is given by:

$ME = z_{\alpha/2} \sqrt{\frac{\hat p (1-\hat p)}{n}}$

And replacing we got:

$ME = 1.96 \sqrt{\frac{0.23*(1-0.23)}{146}} =0.0683$

And the margin of error for this case would be $ME = 0.07$

Step-by-step explanation:

For this case we have the following dataset given:

$n= 146$ represent the sample size

$\hat p =0.23$ represent the estimated proportion of interest

$Conf=0.95$ represent the confidence level

The significance level for this case would be $\alpha=1-0.95=0.05$ and the critical value for this case would be:

$z_{\alpha/2}=1.96$

The margin of error is given by:

$ME = z_{\alpha/2} \sqrt{\frac{\hat p (1-\hat p)}{n}}$

And replacing we got:

$ME = 1.96 \sqrt{\frac{0.23*(1-0.23)}{146}} =0.0683$

And the margin of error for this case would be $ME = 0.07$

4 0

3 years ago