Minimum: 5
Lower Quartile: 10
Median: 14.5
Upper Quartile: 18
Maximum: 22
Well 6x8 = 48 so 8 touchdowns is 48 points
Yes because 56/8 = 7
And 72/8 = 9.
Together they make 7/9.
Answer:
(3,5)
Step-by-step explanation:
Mid-point = (1i+2j+5i+8j)/2
=(6i+10j)/2
=3i+5j
=(3 5)
Answer:
≈50.6
Step-by-step explanation:
Not sure what precision level this problem is looking for, but for right-skewed distributions, we know that the mean is going to be pulled right and therefore the mean should be larger than the median. To a high confidence level, the mean should fall between 50 and 59, or in the third column.
If a single estimation is wanted, assume the values inside each column are uniformly distributed:
![\displaystyle\\\widehat{\mu}=\frac{34.5\cdot 4+...+74.5\cdot 2}{4+9+4+4+2}\approx \boxed{50.6}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5C%5C%5Cwidehat%7B%5Cmu%7D%3D%5Cfrac%7B34.5%5Ccdot%204%2B...%2B74.5%5Ccdot%202%7D%7B4%2B9%2B4%2B4%2B2%7D%5Capprox%20%5Cboxed%7B50.6%7D)