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2 years ago

6

Which of the following angles have a greater measure than angle 5

2 answers:

Alex Ar [27]2 years ago

5 0

Answer:

angle 7 and 3

maria [59]2 years ago

3 0

Answer:

this one is 3

(is this the question you needed help with?)

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Anna makes unique jewelry. The owner of the "Unique" store agreed with Anna to deliver 20 bracelets a week. At the moment, Anna

fgiga [73]

Answer:

7 weeks

Step-by-step explanation:

80 ÷ 20 = 4

She over those four week she makes 17 per week. So,

17 × 4 = 68

Next, divide the product by 20:

68 ÷ 20 = 3.4

But 3.4 is only 3 full weeks so then its 3.

Lastly, add the 3 weeks we just solved for the the 4 weeks from before and you get 7 weeks.

So, Anna will be able to supply the "Unique" store for 7 weeks.

I HOPE I HELPED!!!!!!!!!! :))))))

6 0

2 years ago

Intersection point of Y=logx and y=1/2log(x+1)

GalinKa [24]

Answer:

The intersection is $(\frac{1+\sqrt{5}}{2},\log(\frac{1+\sqrt{5}}{2})$ .

The Problem:

What is the intersection point of $y=\log(x)$ and $y=\frac{1}{2}\log(x+1)$ ?

Step-by-step explanation:

To find the intersection of $y=\log(x)$ and $y=\frac{1}{2}\log(x+1)$ , we will need to find when they have a common point; when their $x$ and $y$ are the same.

Let's start with setting the $y$ 's equal to find those $x$ 's for which the $y$ 's are the same.

$\log(x)=\frac{1}{2}\log(x+1)$

By power rule:

$\log(x)=\log((x+1)^\frac{1}{2})$

Since $\log(u)=\log(v)$ implies $u=v$ :

$x=(x+1)^\frac{1}{2}$

Squaring both sides to get rid of the fraction exponent:

$x^2=x+1$

This is a quadratic equation.

Subtract $(x+1)$ on both sides:

$x^2-(x+1)=0$

$x^2-x-1=0$

Comparing this to $ax^2+bx+c=0$ we see the following:

$a=1$

$b=-1$

$c=-1$

Let's plug them into the quadratic formula:

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$x=\frac{1 \pm \sqrt{(-1)^2-4(1)(-1)}}{2(1)}$

$x=\frac{1 \pm \sqrt{1+4}}{2}$

$x=\frac{1 \pm \sqrt{5}}{2}$

So we have the solutions to the quadratic equation are:

$x=\frac{1+\sqrt{5}}{2}$ or $x=\frac{1-\sqrt{5}}{2}$ .

The second solution definitely gives at least one of the logarithm equation problems.

Example: $\log(x)$ has problems when $x \le 0$ and so the second solution is a problem.

So the $x$ where the equations intersect is at $x=\frac{1+\sqrt{5}}{2}$ .

Let's find the $y$ -coordinate.

You may use either equation.

I choose $y=\log(x)$ .

$y=\log(\frac{1+\sqrt{5}}{2})$

The intersection is $(\frac{1+\sqrt{5}}{2},\log(\frac{1+\sqrt{5}}{2})$ .

6 0

2 years ago

SOMEONE PLEASE HELP ME ASAP PLEASE!!!

Alex17521 [72]

Answer:

BC=10

Step-by-step explanation:

BD-BC=14-4=10

4 0

2 years ago

Read 2 more answers

A car rental company's standard charge includes an initial fee plus an additional fee for each mile driven. The standard charge

zheka24 [161]

answer

c = 20.65 + 0.65M

8 0

2 years ago

(6m^3 -16m^2 + 15m - 40) / (2m^2 + 5)

Helen [10]

6m3 - 16m2 + 15m - 40<span> Simplify ————————————————————— 2m2 + 5 </span>Checking for a perfect cube :

<span> 4.1 </span> <span> 6m3 - 16m2 + 15m - 40</span> is not a perfect cube

Trying to factor by pulling out :

<span> 4.2 </span>     Factoring: <span> 6m3 - 16m2 + 15m - 40</span>

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1:  15m - 40
Group 2: <span> -16m2 + 6m3</span>

Pull out from each group separately :

Group 1:   (3m - 8) • (5)
Group 2: <span> (3m - 8) • (2m2)</span>
               -------------------
Add up the two groups :
              <span> (3m - 8) • </span><span> (2m2 + 5)</span>
<span>Which is the desired factorization</span>

<span>3m-8 is the answer</span>

4 0

2 years ago