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3 years ago

5

GEOMETRY HELP PLEASE!!!!!!! Josh is building an enclosure with recycled cardboard for his collection of model cars his design is

as shown below:
What is the length of side BC in inches?

A) 14
B) 43
C) 49
D) 63

2 answers:

scoray [572]3 years ago

5 0

The answer is D. 63. You have to set up a proportion as shwon in the image.

Kruka [31]3 years ago

5 0

63 - the scale factor is 7

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The distance between Columbus,Ohio and New York City is about 560 miles how many hours would it take the train to travel between

sergey [27]

Since the distance is 560 miles and the bus goes 268 miles per hour, the answer can be given as:
If 268=1 hour
560=?
560/268*1 hour =2(rounded to nearest ones)
Therefore it will take the train approximately 2 hours to travel between both cities.

3 0

3 years ago

What is the answer to number 7b?

Semmy [17]

Increasing it by 10% will be 11.55. To find teen percent all you do is make it a decimal then multiplying it by 10.50

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3 years ago

7. All quadrilaterals have 4 sides and a trapezoid is a quadrilateral. How many sides does a trapezoid have? A: 5 B: 4 C: 3 D: 2

nata0808 [166]

Answer:

B: 4

Step-by-step explanation:

A trapezoid have 4 sides.

Hope it helps you in your learning process

5 0

2 years ago

Read 2 more answers

A rancher wishes to build a fence to enclose a 2250 square yard rectangular field. Along one side the fence is to be made of hea

Bess [88]

Answer:

The least cost of fencing for the rancher is $1200

Step-by-step explanation:

Let <em>x</em> be the width and <em>y </em>the length of the rectangular field.

Let <em>C </em>the total cost of the rectangular field.

The side made of heavy duty material of length of <em>x </em>costs 16 dollars a yard. The three sides not made of heavy duty material cost $4 per yard, their side lengths are <em>x, y, y</em>. Thus

$C=4x+4y+4y+16x\\C=20x+8y$

We know that the total area of rectangular field should be 2250 square yards,

$x\cdot y=2250$

We can say that $y=\frac{2250}{x}$

Substituting into the total cost of the rectangular field, we get

$C=20x+8(\frac{2250}{x})\\\\C=20x+\frac{18000}{x}$

We have to figure out where the function is increasing and decreasing. Differentiating,

$\frac{d}{dx}C=\frac{d}{dx}\left(20x+\frac{18000}{x}\right)\\\\C'=20-\frac{18000}{x^2}$

Next, we find the critical points of the derivative

$20-\frac{18000}{x^2}=0\\\\20x^2-\frac{18000}{x^2}x^2=0\cdot \:x^2\\\\20x^2-18000=0\\\\20x^2-18000+18000=0+18000\\\\20x^2=18000\\\\\frac{20x^2}{20}=\frac{18000}{20}\\\\x^2=900\\\\\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}\\\\x=\sqrt{900},\:x=-\sqrt{900}\\\\x=30,\:x=-30$

Because the length is always positive the only point we take is $x=30$ . We thus test the intervals $(0, 30)$ and $(30, \infty)$

$C'(20)=20-\frac{18000}{20^2} = -25 < 0\\\\C'(40)= 20-\frac{18000}{20^2} = 8.75 >0$

we see that total cost function is decreasing on $(0, 30)$ and increasing on $(30, \infty)$ . Therefore, the minimum is attained at $x=30$ , so the minimal cost is

$C(30)=20(30)+\frac{18000}{30}\\C(30)=1200$

The least cost of fencing for the rancher is $1200

Here’s the diagram:

3 0

2 years ago

Which ordered pair is a solution to the equation y= 6x - 2?

Dmitry [639]

Answer:

(5, 28)

Step-by-step explanation:

y= 6x - 2

Verifying pairs:

(1,0)

0 = 6*1 - 2
0 = 4 - incorrect

(5, 28)

28 = 6*5 - 2
28 = 30 -2
28 = 28 - correct

(6, 20)

20 = 6*6 - 2
20 = 36 - 2
20 = 34 - incorrect

(3, 19)

19 = 6*3 - 2
19 = 18 - 2
19 = 16 - incorrect

4 0

2 years ago