Solve this please -3 1/6+6 2/3

Jamie and Stella are saving money to sign up for a school trip to Washington, D.C. In order to sign up for the trip, they must p

rusak2 [61]

The answer is incomplete. Here is the complete question:

Jamie and Stella are saving money to sign up for a school trip to Washington, D.C. In order to sign up for the trip, they must pay $600 upfront. Jamie earns his money by washing cars for $25 each. Stella earns her money by making pecan pies for $15 each. Jamie earns more money than Stella does because Stella only has enough supplies to make 40 pies. let x represent the number of cars Jamie washes. Let y represent the number of pies Stella makes.

Part 1: Write a constraint (an inequality) to represent how much money Jamie needs for his trip.

Part 2: Write a constraint (an inequality) to represent how much money Stella needs for her trip.

Part 3: Write a constraint (an inequality) to represent the limitations of Stella's supplies.

Part 4: Can Stella afford to sign up for the trip with the money she earns? Explain your answer and show any work that might support your answer.

Answer:

Part 1: $25x\geq 600$

Part 2: $15y\geq 600$

Part 3: $y\leq 40$

Part 4: Yes, she makes exactly 600 dollars by making 40 pies.

Step-by-step explanation:

Given:

Total money needed for the trip is 600 dollars.

Money earnt by Jamie for washing one car is $25.

Money earnt by Stella for making one pie is $15.

Let $x$ represent the number of cars Jamie washes. Let $y$ represent the number of pies Stella makes.

Part 1:

Since the cost for washing one car is $25

Therefore, the cost of washing $x$ cars is $25x$ .

Now, in order to sign up for the trip, money obtained from car washing must be greater than or equal to $600.

Therefore, $25x\geq 600$

Part 2:

Since the cost for making one pie is $15

Therefore, the cost of making $y$ pies is $15y$ .

Now, in order to sign up for the trip, money obtained from pie making must be greater than or equal to $600.

Therefore, $15y\geq 600$

Part 3:

As per the question, the maximum number of pies that Stella can make is 40. So, the value of $y$ can't exceed 40 and must be less than or equal to 40. Therefore,

$y\leq 40$

Part 4:

Now, in order to sign up for the trip, Stella's total earning must be at least $600. So, $15y=600$ is the minimum condition for signing up for the trip. Now, let us solve the above equation for $y$ . This gives,

$15y=600\\y=\frac{600}{15}=40$

Therefore, minimum number of pies required for signing up for the trip is 40 and luckily that's the maximum supply Stella has for pies. Therefore, she can sign up for the trip by making all the 40 pies and earning a total of 600 dollars.

8 0

3 years ago

Find the least common denominator of the fractions 2/8 and 3/5

Ierofanga [76]

Answer:

40

Step-by-step explanation:

2/8 = 10/40

3/5 = 24/40

3 0

3 years ago

you rent a canoe for 5$ per hour.Your cost before the tax is added is 12.50. write and solve an equation to find the total numbe

Basile [38]

Answer: The equation is 5x = 12.50 and you will have the canoe for 2 and half hours or 2 hours 30 minutes.

Step-by-step explanation:

You rent the canoe for 5 dollars per hour and that can be represented by the expression 5x. After sometime you paid $12.50 meaning that to find the number of hours that you need the canoe, we need to set 5x to equal 12.50.

5x = 12.50 Solve for x by divide both sides by 5.

x = 2.5

This means you will need the canoe for 2 and half hours.

8 0

3 years ago

Why does these expressions 2(30x-24), 3(20x-16), and 4(15x-12) have the same expansion?

MariettaO [177]

The expressions have the same expansion I'd say because the pairs 2 and 30, 3 and 20, and 4 and 15 because they are all equivalent to 60 because they are all factors of 60.

Same goes with the other pairs, because they are all equivalent to 48 because they are all factors of 48.

6 0

3 years ago

One solution to the problem below is 5 what ya the other solution a^2-25=0

Alex

-5

a^2-25=0

a^2=25

take the square root of both sides

a=5, and -5

5 0

3 years ago