Photomath i use it for my math all the time it gives you the option for how you wanna solve it and shows you how to solve it
Graph 2 should be right because it moves up 1 because of the +1 that is in the parentheses.
Answer:
98 ft²
Step-by-step explanation:
There are a couple of ways you can think about this one. Perhaps easiest is to treat it as a square with a triangle cut out of it. The cutout triangle has a base (across the top) of 14 ft and a height of 14 ft, so its area is ...
A = (1/2)(14 ft)(14 ft) = 98 ft²
Of course the area of the square from which it is cut is ...
A = (14 ft)² = 196 ft²
So, the net area of the two triangles shown is ...
A = (196 ft²) - (98 ft²) = 98 ft²
_____
Another way to work this problem is to attack it directly. Let the base of the left triangle be x. Then the base of the right triangle is 14-x, and their total area is ...
A = A1 + A2 = (1/2)(x ft)(14 ft) + (1/2)((14-x) ft)(14 ft)
We can factor out 7 ft to get ...
A = (7 ft)(x ft + (14 -x) ft)
A = (7 ft)(14 ft) = 98 ft²
1. y axis can repeat/x cannot repeat
2. Parabola symmetrically across y-axis
(10x)^ (-3)
= 1/ [(10x)^3]
= 1/ [10^3* x^3]
= 1/ (1000x^3)
The final answer is 1/ (1000x^3), and I don't think there is a correct option to choose from. ( option c would be correct if it were written with round brackets)
Hope this helps~
