Answer:
they will have 15.02 left over
Step-by-step explanation:
Alex:
21*.35=7.35
21-7.35= 13.65
13.65*.10=1.37
13.65+1.37=15.02
Lara:
21*.65=13.65
13.65*1.10=15.02
They are both correct but the easier way to get the answer is Alex's way.
The temperature T in Kelvin (K) is equal to the temperature T in degrees Celsius (°C) plus 273.15:
T(K) = T(°C) + 273.15;
So, T(K) = -25 + 273.15;
T(K) = 248.15;
The correct answer is a.
Answer:
D)5.1,7,2.3
Step-by-step explanation:
the measures of side lengths for a triangle :
any two sides added up must be bigger than the measure of the third side
and any two sides' difference must be smaller than the third side.
Answer:
q = -5
q = 5
Step-by-step explanation:
Since there is no constant value. This must be a special case.
So,
(q+5)(q-5)
q = -5
q = 5
Answer:
Step-by-step explanation:
Given that,
- p ( probability that the child has disease) = 25% = 0.25
- n = number of children = 3
The probability mass function of binomial distribution is,
- (P = X) = (nCx) X (p)^x X (1 - p)^n-x ; x = 0, 1, 2 ,3
- = 3Cx X (0.25)^x X (1 - 0.25)^3-x ; ( n = 3, p = 0.25
a) P ( two will have disease)
p ( X = 2) = 3C2 X (0.250^2 X (1 - 0.25) ^3-2
= 0.1406
b) P ( none will have disease)
p (X = 0) = 3C0 X (0.25)^0 X (1 - 0.25)^3-0
= 0.4219
c) P (neither having the disease nor being a carrier) = 25% = 0.25
The probability that at least one will neither having the disease nor being a carrier ;
P(X> or equals to) = 1 - P(X < 1)
= 1 - P( X = 0)
= 1 - 3C0 X (0.25)^0 X (1 - 0.25)^3-0
= 0.5781
d) p( the first child with the disease will the be 3rd child)
P(X = x) = (1-p)^x-1 X p
p( X= x) = ( 1 - 0.25 )^x -1 X 0.25
for third child = P(X = 3) = (1 - 0.25)^3-1 X (0.25)
= 0.1406