The answer is 50.
i came to this conclusion when using this equation: 15x+5=2+16x
for x, i got 3.
using my x-value, i replace “x” with “3” when solving angle measure, “15(3)+5”
15(3)+5= 50
there is your answer!
Answer:
i got them right
Step-by-step explanation:
A is translated and congruent
B is dilated and similar
C is reflected and congruent
depending on how your quiz is when is say and then a word like "congruent" that word is the one you type in and the other word translated,dilated and reflected is from the drop down bar. any questions on how this is set up
<span>Two algebraic expressions are said to be equivalent if their values obtained by substituting the values of the variables are same.</span>
Given,
The coordinates of the point on the circle is (-4, -2).
The coordinates of the center of the circle is (-8, -10).
Reuired
The length of the center of the circle.
By using the distance formula, the radius of the circle can be calculated.
The distance formula is,

Substituting the value of the coordinates of the points,
![\begin{gathered} Distance=\sqrt{(-10-(-2))^2+(-8-(-4))^2} \\ =\sqrt{(-10+2)^2+(-8+4)^2} \\ =\sqrt{(-8)^2+(-4)^2} \\ =\sqrt{64+16} \\ =\sqrt{80} \\ =\sqrt{4\times4\times5} \\ =4\sqrt[]{5} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20Distance%3D%5Csqrt%7B%28-10-%28-2%29%29%5E2%2B%28-8-%28-4%29%29%5E2%7D%20%5C%5C%20%3D%5Csqrt%7B%28-10%2B2%29%5E2%2B%28-8%2B4%29%5E2%7D%20%5C%5C%20%3D%5Csqrt%7B%28-8%29%5E2%2B%28-4%29%5E2%7D%20%5C%5C%20%3D%5Csqrt%7B64%2B16%7D%20%5C%5C%20%3D%5Csqrt%7B80%7D%20%5C%5C%20%3D%5Csqrt%7B4%5Ctimes4%5Ctimes5%7D%20%5C%5C%20%3D4%5Csqrt%5B%5D%7B5%7D%20%5Cend%7Bgathered%7D)
Hence,
Answer:
Price of each phone: 
Price of each accessory: 
Step-by-step explanation:
Let be "p" the price in dollars of each phone and "a" the price in dollars of each accessory.
Set up a system of equations:

You can use the Elimination Method to solve the system.
Multiply the second equation by -2 and add both equations:

Substitute the value of "a" into the first equation and solve for "p":
