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Lyrx [107]
3 years ago
10

511 3 Find the missing exponent. 54 Exponent only in the answer box 5? I need help with this asap.​

Mathematics
1 answer:
defon3 years ago
5 0

Answer:

45 is it

Step-by-step explanation:

hope it helps...

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A student writes "the quotient of 5 and x" to describe the algebraic expression -
pashok25 [27]

For this case we have to:

\frac {a} {b} = c

Where:

a: It's the Dividend

b: It is the Divider

c: Is the Quotient

Thus, the expression "the quotient of 5 and x" can be represented as:

\frac {5} {x} = y

Where "y" is the quotient of 5 and x.

ANswer:

\frac {5} {x} = y

5 0
3 years ago
Which of the following expressions are equivalent to -(-8/-4)1. -(-8/4)
PSYCHO15rus [73]

Answer:

44/5+3 2/10- 1 1/5= 44/5 + 3 1/5 - 11/5 = 44/5+ 16/5- 1 1/5 44/5+16/5-6/5 44/5+2 54/5=54/5 which equals 10 4/5 is your answer I hope this helped you! (;

Step-by-step explanation:

4 0
3 years ago
find the common difference of the arithmetic sequence. 6, 9.4, 12.8, 16.2, . . . a. 3.4 b. 15.4 c. 1.6 d. –1.6
Alexeev081 [22]
9.4 - 6 = 3.4
12.8 - 9.4 = 3.4
16.2 -12.8 = 3.4

hence the difference between the terms is common and = 3.4
5 0
4 years ago
A dairy farmer wants to mix a 85% protein supplement and a standard 55% protein ration to make 1200 pounds of a high-grade 80% p
mr_godi [17]

The diary farmer should use 1000 pounds of 85 % protien and 55 % of 200 pounds to make 1200 pounds of a high-grade 80% protein ration

<em><u>Solution:</u></em>

Let the amount of 85 % protien supplement be "x"

Then amount of 55 % protien be (1200 - x)

According to given question,

85 % of "x" protien supplement + 55 % of 1200 - x protien used to get 80 % of 1200 pounds

85 % of x + 55 % of (1200 - x) = 80 % of 1200

\frac{85}{100} \times x + \frac{55}{100} \times (1200 - x) = \frac{80}{100} \times 1200\\\\0.85x + 0.55(1200 - x) = 960\\\\0.85x + 660 - 0.55x = 960\\\\0.3x = 960 - 660\\\\0.3x = 300\\\\x = 1000

Pounds of 85 % protien used = 1000 pounds

Then pounds of 55 % protien used = 1200 - 1000 = 200 pounds

Thus he should use 1000 pounds of 85 % protien and 200 pounds of 55 % protien to get 1200 pounds of a high-grade 80% protein ration

7 0
3 years ago
Compute the determinant using a cofactor expansion across the first row. Also compute the determinant by a cofactor expansion do
V125BC [204]

Answer:

Step-by-step explanation:

It is given that

\Delta=\begin{vmatrix}3&0&3\\2 &3&3\\0 &4&-2\end{vmatrix}

By cofactor expansion across the first row, we get

\Delta=a_{11}C_{11}+a_{12}C_{12}+a_{13}C_{13}

\Delta=3\left[(-1)^{1+1}\begin{vmatrix}3&3\\4&-2\end{vmatrix}\right]+0\left[(-1)^{1+2}\begin{vmatrix}2&3\\0&-2\end{vmatrix}\right]+3\left[(-1)^{1+3}\begin{vmatrix}2&3\\0&4\end{vmatrix}\right]

\Delta=3\left[-18\right]+0\left[(-1)(-4)\right]+3\left[8\right]

\Delta=-54+0+24

\Delta=-30

Therefore, the value of determinant is -30.

By cofactor expansion across the second column, we get

\Delta=a_{12}C_{12}+a_{22}C_{22}+a_{32}C_{32}

\Delta=0\left[(-1)^{2+1}\begin{vmatrix}2&3\\0&-2\end{vmatrix}\right]+3\left[(-1)^{2+2}\begin{vmatrix}3&3\\0&-2\end{vmatrix}\right]+4\left[(-1)^{3+2}\begin{vmatrix}3&3\\2&3\end{vmatrix}\right]

\Delta=0\left[(-1)(-4)\right]+3\left[(-6)\right]+4\left[(-1)3\right]

\Delta=-18-12

\Delta=-30

Therefore, the value of determinant is -30.

7 0
4 years ago
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