51) 5x-1=0 and x+6=0
5x=1, x=1/5 and x=-6
2 solutions x=1/5 and x=-6
52)x(2x+3)=0
2x=0 and 2x+3 =0
x=0 and x=-3/2=-1.5
53) x(5x-1)=0
x=0 and 5x-1=0
x=0 and x=1/5
54) z(4z+7) =0
z=0 and 4z+7=0
z=0 and z= - 7/4 = -1.75
z=0 and z=-1.75
Answer:
height of the cone = 4.01273885 units
Step-by-step explanation:
Volume of a cone(V) is given by:
....[1]
where,
r is the radius and h is the height of the cone.
As per the statement:
A cone with radius 5 units and ts volume is 105 cubic units
⇒r = 5 units and V = 105 cubic units
Substitute these given values and use
in [1] we have;

Multiply both sides by 3 we have;
⇒
Divide both sides by 78.5 we have;

or
h = 4.01273885 units
Therefore, the height of the cone is, 4.01273885 units
√129 is less than
.

Let us first solve for √129.
➝
➝
Now,
➝
➝
Clearly,
➵
➵
Hence, √129 is less than
.
