Factorise a^4 -(a+b)^4

Mathematics

1 answer:

Flura [38]3 years ago

8 0

Step-by-step explanation:

${a}^{4} - (a + b)^{4} \\ = ( {a}^{2})^{2} - \{ (a + b)^{2} \}^{2} \\ = \{ {a}^{2} - (a + b)^{2} \}\{ {a}^{2} + (a + b)^{2} \} \\ = \{ {a} + (a + b) \}\ \: \{ {a} - (a + b) \}\{ {a}^{2} + (a + b)^{2} \} \\ = \{ {a} + a + b \}\ \: \{ {a} - a - b\}\{ {a}^{2} + a^{2} + b^{2} + 2ab\} \\ = (2a + b)( - b)(2 {a}^{2} + {b}^{2} + 2ab ) \\ = - b(2a + b)(2 {a}^{2} + {b}^{2} + 2ab ) \\$

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Leslie babysat the Thompson twins for 110 hours during the summer. This was 5 1/2 times as many hours as Tom babysat the twins.

Anvisha [2.4K]

To solve this, you do:
110 divided by 5 1/2.
If you want your answer in fraction form, you do:
110/1 ÷ 11/2 (the improper fraction form)
To multiply, flip the second fraction to change from dividing to mutiplying:
110/1 × 2/11
Multiply across
110 × 2 = 220 and 1 × 11 = 11
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Simplify:
220 ÷ 11 = 20
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Answer:

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