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hjlf
4 years ago
8

Use point-slope form to write the equation of the line in slope-intercept form that passes through the points (0, -5) and (-3, 4

).
Slope formula: equation

Point-slope form: y – y1 = m(x – x1)

Slope-intercept form: y = mx + b

Choose the equation of the line
Mathematics
2 answers:
Anna007 [38]4 years ago
5 0

The point slope form of this line is y+5=m(x).  Now, you need to find m (the slope) of the line using the formula (y1-y2)/(x1-x2):

(-5-4)/(0--3)

-9/3

-3

The complete point slope formula is: y+5=-3x.

Now, to fin the slope intercept form, just solve for y:

y+5=-3x

<em>*Subtract 5 from both sides*</em>

y=-3x-5

Hope this helps!!

Andru [333]4 years ago
3 0

Answer:

y = -3x - 5.

Step-by-step explanation:

y – y1 = m(x – x1)

The slope m =  rise /run = (4 - -5) / (-3 - 0)

= 9/-3

= -3.

Using the point (0, -5) and m =-3 in the point-slope:

y - -5 = -3(x - 0)

y + 5 = -3x

y = -3x - 5 is the required  slope-intercept form.

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5.\\(x+3)^2+7=-2\qquad|-7\\\\(x+3)^2=-9 < 0\\\\\text{NO REAL SOLUTION}\\\\(x+3)^2=-9\to x+3=\pm\sqrt{-9}\\\\x+3=-3i\ \vee\ x+3=3i\qquad|-3\\\\\boxed{x=-3-3i\ \vee\ x=-3+3i}

6.\\4(x-10)^2=25\qquad|:4\\\\(x-10)^2=\dfrac{25}{4}\to x-10=\pm\sqrt{\dfrac{25}{4}}\\\\x-10=-\dfrac{\sqrt{25}}{\sqrt4}\ \vee\ x-10=\dfrac{\sqrt{25}}{\sqrt4}\\\\x-10=-\dfrac{5}{2}\ \vee\ x-10=\dfrac{5}{2}\\\\x-10=-2.5\ \vee\ x-10=2.5\qquad|+10\\\\\boxed{x=7.5\ \vee\ x=12.5}

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