Answer:
0.5 ; 0.475 ; 0.689 ; 0.4013
Step-by-step explanation:
Given that:
Rate of production of defective batteries p = 0.05
Number of batteries produced (n) = 10
The expected number of defective batteries = mean = n * p = 10 * 0.05 = 0.5 batteries
Variance of defective batteries :
Var(X) = n * p * q ; q = 1 - p
Hence,
Var(X) = 10 * 0.05 * 0.95 = 0.475
Standard deviation (X) = sqrt(variance) = sqrt(0.475) = 0.689
Probability that atleast 1 battery is defective :
Using the binomial probability function
P(x ≥ 1) = 1 - p(x = 0)
= 1 - q^n
= 1 - 0.95^10
= 1 - 0.59873693923837890625
= 0.40126306076162109375
= 0.4013
The answer is x=45... hope I helped!
x/3=15
multiply each side by 3
x=45
Answer: area = 170 inches
Step-by-step explanation:
If you count the number of seconds between the flash of lightning and the sound of thunder, and then divide by 5, you'll get the distance in miles to the lightning: 5 seconds = 1 mile, 15 seconds = 3 miles, 0 seconds = very close. Keep in mind that you should be in a safe place while counting.
Answer:
(a) The probability of waiting less than 12 minutes between successive speeders using the cumulative distribution function is 0.7981.
(b) The probability of waiting less than 12 minutes between successive speeders using the probability density function is 0.7981.
Step-by-step explanation:
The cumulative distribution function of the random variable <em>X, </em>the waiting time, in hours, between successive speeders spotted by a radar unit is:

(a)
Compute the probability of waiting less than 12 minutes between successive speeders using the cumulative distribution function as follows:

The probability is:


Thus, the probability of waiting less than 12 minutes between successive speeders using the cumulative distribution function is 0.7981.
(b)
The probability density function of <em>X</em> is:

Compute the probability of waiting less than 12 minutes between successive speeders using the probability density function as follows:

![=8\times [\frac{-e^{-8x}}{8}]^{0.20}_{0}\\\\=[-e^{-8x}]^{0.20}_{0}\\\\=(-e^{-8\times 0.20})-(-e^{-8\times 0})\\\\=-0.2019+1\\\\=0.7981](https://tex.z-dn.net/?f=%3D8%5Ctimes%20%5B%5Cfrac%7B-e%5E%7B-8x%7D%7D%7B8%7D%5D%5E%7B0.20%7D_%7B0%7D%5C%5C%5C%5C%3D%5B-e%5E%7B-8x%7D%5D%5E%7B0.20%7D_%7B0%7D%5C%5C%5C%5C%3D%28-e%5E%7B-8%5Ctimes%200.20%7D%29-%28-e%5E%7B-8%5Ctimes%200%7D%29%5C%5C%5C%5C%3D-0.2019%2B1%5C%5C%5C%5C%3D0.7981)
Thus, the probability of waiting less than 12 minutes between successive speeders using the probability density function is 0.7981.