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Fofino [41]
3 years ago
6

A university wanted to survey alumni about their interest in lifelong learning classes. They mailed questionnaires to a random s

ample of 600 alumni from their database of over 30,000 recent graduates. Would you consider this population to be effectively infinite?
Mathematics
1 answer:
anzhelika [568]3 years ago
7 0

Answer:

Yes, it is effectively infinite

Step-by-step explanation:

An effectively infinite population refers to population from which it is possible to obtain a computable sub-population from it, and it is also effectively possible to construct another new sub-population from that same population that will not have elements already contained in the first sub-population.

The attributes of this kind of population is called effective infinity.

Database of recent graduates of any university possess this kind of attributes since it is possible to obtain another over 30,000 recent graduates from the database that will not have elements of the first 30,000.

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1. A certain manufacturing process to build phone batteries results in the production of defective batteries at a rate of 5% (0.
lesya [120]

Answer:

0.5 ; 0.475 ; 0.689 ; 0.4013

Step-by-step explanation:

Given that:

Rate of production of defective batteries p = 0.05

Number of batteries produced (n) = 10

The expected number of defective batteries = mean = n * p = 10 * 0.05 = 0.5 batteries

Variance of defective batteries :

Var(X) = n * p * q ; q = 1 - p

Hence,

Var(X) = 10 * 0.05 * 0.95 = 0.475

Standard deviation (X) = sqrt(variance) = sqrt(0.475) = 0.689

Probability that atleast 1 battery is defective :

Using the binomial probability function

P(x ≥ 1) = 1 - p(x = 0)

= 1 - q^n

= 1 - 0.95^10

= 1 - 0.59873693923837890625

= 0.40126306076162109375

= 0.4013

7 0
3 years ago
X over 3 = 15 answer is, work it out
beks73 [17]
The answer is x=45... hope I helped!
x/3=15
multiply each side by 3
x=45
6 0
4 years ago
Read 2 more answers
A watercolor painting is 15 inches long by 8 inches wide Ramen makes a border around the watercolor painting by making a mat tha
Sveta_85 [38]

Answer: area = 170 inches

Step-by-step explanation:

3 0
4 years ago
The time between a flash of lightning and the sound of its thunder can be used to estimate the distance you are from a lightning
julia-pushkina [17]

If you count the number of seconds between the flash of lightning and the sound of thunder, and then divide by 5, you'll get the distance in miles to the lightning: 5 seconds = 1 mile, 15 seconds = 3 miles, 0 seconds = very close. Keep in mind that you should be in a safe place while counting.

3 0
3 years ago
3.14 The waiting time, in hours, between successive speeders spotted by a radar unit is a continuous random variable with cumula
vovangra [49]

Answer:

(a) The probability of waiting less than 12 minutes between successive speeders using the cumulative distribution function is 0.7981.

(b) The probability of waiting less than 12 minutes between successive speeders using the probability density function is 0.7981.

Step-by-step explanation:

The  cumulative distribution function of the random variable <em>X, </em>the waiting time, in hours, between successive speeders spotted by a radar unit is:

F(x)=\left \{ {{0;\ x

(a)

Compute the probability of waiting less than 12 minutes between successive speeders using the cumulative distribution function as follows:

12\ \text{minutes}=\frac{12}{60}=0.20\ \text{hours}

The probability is:

P(X

                  =(1-e^{-8x})|_{x=0.20}\\\\=1-e^{-8\times 0.20}\\\\=0.7981

Thus, the probability of waiting less than 12 minutes between successive speeders using the cumulative distribution function is 0.7981.

(b)

The probability density function of <em>X</em> is:

f_{X}(x)=\frac{d F (x)}{dx}=\left \{ {{0;\ x

Compute the probability of waiting less than 12 minutes between successive speeders using the probability density function as follows:

P(X

                  =8\times [\frac{-e^{-8x}}{8}]^{0.20}_{0}\\\\=[-e^{-8x}]^{0.20}_{0}\\\\=(-e^{-8\times 0.20})-(-e^{-8\times 0})\\\\=-0.2019+1\\\\=0.7981

Thus, the probability of waiting less than 12 minutes between successive speeders using the probability density function is 0.7981.

3 0
3 years ago
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