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mamaluj [8]
3 years ago
13

Angie need to buy 140 candles for a party. Each package has 8 candles. How many packages should Angie buy?

Mathematics
2 answers:
Darya [45]3 years ago
7 0

Answer

17 is the answer

Step by step answer

     

AfilCa [17]3 years ago
6 0
17.5 packages. You divide 8 and 140
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What is the quotient?<br> 7)<br> 126<br> А.<br> 16<br> B.<br> 17<br> С<br> 18<br> D<br> 19
Hunter-Best [27]

Answer:

C

Step-by-step explanation:

The quotient is 18

6 0
3 years ago
A circle is centered at the point (5, -4) and passes through the point (-3, 2).
zepelin [54]

Answer:

(x-5)^2+(y+4)^2=100

Step-by-step explanation:

As we know the given points

Center = (5, -4)

and

Point on circle = (-3,2)

The distance between point on circle and center will give us the radius of circle

So,

The formula for distance is:

\sqrt{(x_{2}-x_{1} )^{2}+(y_{2}-y_{1})^{2}}\\Taking\ center\ as\ point\ 1\ and\ the\ other\ point\ as\ point\ 2\\d=\sqrt{(-3-5)^{2}+(2-(-4))^{2}}\\d=\sqrt{(-8)^{2}+(2+4)^{2}}\\d=\sqrt{(-8)^{2}+(6)^{2}}\\\\d=\sqrt{64+36}\\d=\sqrt{100} \\ d=10\\So\ the\ radius\ is\ 10

The standard form of equation of circle is:

(x-h)^{2}+(y-k)^{2}=r^{2}

where h and k are the coordinates of the center. So putting in the value:

(x-5)^{2}+(y-(-4))^{2}=(10)^{2}\\(x-5)^{2}+(y+4)^{2}=100

8 0
3 years ago
What is the slope, and what is the y-intercept of the line?
Oliga [24]
General\ equation\ for\ line\ in\ slope\ intercept\ form:&#10;\\\\y=ax+b\\&#10; a-slope\\ &#10;b-intercept\\\\ &#10;y=\frac{5}{4}x+9\\\\&#10;slope=\frac{5}{4}\\\\intercept=9
4 0
3 years ago
What is the percentage of change from 12 to 19
tiny-mole [99]

Answer:

(19-12):12*100 =

(19:12-1)*100 =

158.33333333333-100 = <u>58.33</u>

3 0
2 years ago
The Springer Dog Food Company makes dry dog food from two ingredients. The two ingredients (A and B) provide different amounts o
Nataly [62]

Answer:

a) Objective function (minimize cost):

C=0.50A+0.20B

Restrictions

Proteins per pound: 16A+8B\leq 12

Vitamins per pound: 4A+8B\leq 6

Non-negative values: A,B\geq0

b) Attached

c) The optimum solution (minimum cost) is 0 pounds of ingredient A and 0.75 pounds of ingredient B. The cost is $0.15 per ration.

d) The optimum solution changes. The cost is now 0 pounds of ingredient A and 0.625 pounds of ingredient B. The cost is $0.125 per ration.

Step-by-step explanation:

a) The LP formulation for this problem is:

Objective function (minimize cost):

C=0.50A+0.20B

Restrictions

Proteins per pound: 16A+8B\leq 12

Vitamins per pound: 4A+8B\leq 6

Non-negative values: A,B\geq0

b) The feasible region is attached.

c) We have 3 corner points. In one of them lies the optimal solution.

Corner A=0 B=0.75

C=0.50*0+0.20*0.75=0.15

Corner A=0.5 B=0.5

C=0.50*0.5+0.20*0.5=0.35

Corner A=0.75 B=0

C=0.50*0.75+0.20*0=0.375

The optimum solution (minimum cost) is 0 pounds of ingredient A and 0.75 pounds of ingredient B. The cost is $0.15 per ration.

d) If the company requires only 5 units of vitamins per pound rather than 6, one of the restrictions change.

The feasible region changes two of its three corners:

Corner A=0 B=0.625

C=0.50*0+0.20*0.625=0.125

Corner A=0.583 B=0.333

C=0.50*0.583+0.20*0.333=0.358

Corner A=0.75 B=0

C=0.50*0.75+0.20*0=0.375

The optimum solution changes. The cost is now 0 pounds of ingredient A and 0.625 pounds of ingredient B. The cost is $0.125 per ration.

3 0
3 years ago
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