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Ganezh [65]
3 years ago
9

Find the area of a circle with a circumference of 6.28

Mathematics
2 answers:
Bogdan [553]3 years ago
6 0

Answer:

Step-by-step explanation:

Circumfernece of circle = 2πr

6.28 = 2πr

r = 6.28/2π

r = 1 unit

Area A = πr²

A = 3.14 × 1²

A = 3.14square unit

natita [175]3 years ago
4 0

Answer:

3.142

Step-by-step explanation:

C = 2πr (circumference of a circle)

6.28 = 2πr

r = 6.28 / 2π

r = 6.28 / 2 * 3.142

r = 6.26 / 6.284

r = 0.996

r = 1 (approximately)

Let's solve for Area!

Area of a circle is :

A = πr^2

A = 3.241 * 1 ^2

A = 3.142 or π ( base on the option given in the question.

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What does (-3/4)(-4/7)(-2/3 equal to please show work!?
mestny [16]

Answer:

-2/7 0r 2/-7 or the negative sign is in the middle

Step-by-step explanation:

(-3/4)(-4/7)= 3/7

3/7 x -2/3= -2/7

5 0
3 years ago
a half cup of pancakes mix has 5% total daily allowance of cholesterol. the total daily allowance of cholesterol 300 mg. how muc
arsen [322]
Hi there!

Since we know that the pancake mix has 5% of the daily allowance, which is 300 mg, we can just multiply 300 mg with 5 percent to get our answer.

First, let's divide 5% by 100% to know what we are going to multiply 300 mg with.

5% / 100% = 0.05

Let's multiply 300 mg with 0.05

0.05 * 300 = 15 mg

Thus, a 1/2 cup of pancake mix has 15 mg of cholesterol.

Have an awesome day! :)
6 0
3 years ago
Graph the system by using technology. What is the y-coordinate of the solution?
son4ous [18]
Take second equation here, 
2x + 9 = -12
2x = -12 - 9
2x = -21
Multiply by 2, 
4x = -42

Now, substitute the vaue of 4x in 1st equation, 
-42 - y = 2
-y = 2 + 42
y = -44

In short, Your Answer would be -44

Hope this helps!
3 0
4 years ago
Which of the following is not a standard way to write 7 times 8
tankabanditka [31]
The standard way to write it is 
7 x 8 = 56
6 0
3 years ago
Read 2 more answers
PLEASE HELP!!! 15 PTS!!
kherson [118]

Answer:

\large\boxed{C.\ (2,\ -45^o)}

Step-by-step explanation:

Regular coordinates (x, y)

Polar coordinates (r, φ)

r=\sqrt{x^2+y^2}\\\\\psi=\arctan\frac{y}{x}

We have the point

(\sqrt2,\ -\sqrt2)

Substitute:

r=\sqrt{(\sqrt2)^2+(-\sqrt2)^2}=\sqrt{2+2}=\sqrt4=2\\\\\psi=\arctan\left(\frac{-\sqrt2}{\sqrt2}\right)=\arctan(-1)=-45^o

6 0
3 years ago
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