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yuradex [85]
3 years ago
6

{(\frac{2}{3})^{2} }" alt="\sqrt[6]{(\frac{2}{3})^{2} }" align="absmiddle" class="latex-formula"> as a power
Mathematics
1 answer:
miskamm [114]3 years ago
5 0

Answer:

\frac{2}{3}^{\frac{1}{3}}

Step-by-step explanation:

The n-th root is the same thing as the denominator of an exponent.

For example. \sqrt[3]{x} = x^{\frac{1}{3}}

and \sqrt[4]{x} = x^{\frac{1}{4}}

and \sqrt{x} = x^{\frac{1}{2}}

So

\sqrt[6]{\frac{2}{3}^{2}} = \frac{2}{3}^{(2)(\frac{1}{6})} = \frac{2}{3}^{\frac{2}{6}} = \frac{2}{3}^{\frac{1}{3}}

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Answer:

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4 0
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