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yuradex [85]
3 years ago
6

{(\frac{2}{3})^{2} }" alt="\sqrt[6]{(\frac{2}{3})^{2} }" align="absmiddle" class="latex-formula"> as a power
Mathematics
1 answer:
miskamm [114]3 years ago
5 0

Answer:

\frac{2}{3}^{\frac{1}{3}}

Step-by-step explanation:

The n-th root is the same thing as the denominator of an exponent.

For example. \sqrt[3]{x} = x^{\frac{1}{3}}

and \sqrt[4]{x} = x^{\frac{1}{4}}

and \sqrt{x} = x^{\frac{1}{2}}

So

\sqrt[6]{\frac{2}{3}^{2}} = \frac{2}{3}^{(2)(\frac{1}{6})} = \frac{2}{3}^{\frac{2}{6}} = \frac{2}{3}^{\frac{1}{3}}

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Evaluate the expression below.<br> 18 - 71.4 + 3(-1)<br> 0 1<br> 0-7<br> 0-1<br> 07
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3 years ago
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vampirchik [111]

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Step-by-step explanation:

We can use ratios to solve

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----------------- = -------------

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4 0
3 years ago
Simplify 6 - 3(4 - 3x)<br> -3x - 6<br> 9x + 18<br> 9x - 6
svet-max [94.6K]

Answer:

6 (19 x - 2)

Step-by-step explanation:

Simplify the following:

6 - 3 (4 - 3 x) - 3 x - 6×9 x + 18×9 x - 6

-6×9 = -54:

6 - 3 (4 - 3 x) - 3 x + -54 x + 18×9 x - 6

18×9 = 162:

6 - 3 (4 - 3 x) - 3 x - 54 x + 162 x - 6

Grouping like terms, 6 - 3 (4 - 3 x) - 3 x - 54 x + 162 x - 6 = (-3 x - 54 x + 162 x) - 3 (4 - 3 x) + (6 - 6):

(-3 x - 54 x + 162 x) - 3 (4 - 3 x) + (6 - 6)

-3 x - 54 x + 162 x = 105 x:

105 x - 3 (4 - 3 x) + (6 - 6)

6 - 6 = 0:

105 x - 3 (4 - 3 x)

-3 (4 - 3 x) = 9 x - 12:

9 x - 12 + 105 x

Grouping like terms, 105 x + 9 x - 12 = (105 x + 9 x) - 12:

(105 x + 9 x) - 12

105 x + 9 x = 114 x:

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Factor 6 out of 114 x - 12:

Answer: 6 (19 x - 2)

7 0
3 years ago
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Ugo [173]

Answer:

Step-by-step explanation:

2x^2-6x+10=0

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square is always positive so there is no solution

5 0
3 years ago
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