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vfiekz [6]
3 years ago
14

Find the measurement indicated in each parallelogram pls help

Mathematics
1 answer:
devlian [24]3 years ago
6 0
I can’t see the question
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I WILL AWARD BRAINLIEST!! PLEASE HELP!! Given: ΔABC, AB = AC X ∈ AC , Y ∈AB AX = AY Prove: BX = CY m∠ABC = m∠ACB △ABX≅△____, by
EleoNora [17]

Answer:

△ABX ≅ △ACY, by reason that they are equal and congruent to each other.

I hope this answers your question.

6 0
3 years ago
Choose the expression that represents "three less
Anna35 [415]

Answer:

none of your options are right

Step-by-step explanation:

<h2>Three less than seven times a number:</h2>

<u><em>three : 3, less than : (-), seven : 7, times : (multiplication symbol), a number : (x)</em></u>

<u><em>the answer is : 3 - 7 (x)</em></u>

                       <u><em>: 3-7x</em></u>

5 0
2 years ago
4. Find the standard from of the equation of a hyperbola whose foci are (-1,2), (5,2) and its vertices are end points of the dia
Ad libitum [116K]

The <em>standard</em> form of the equation of the hyperbola that satisfies all conditions is (x - 2)²/4 - (y - 2)²/5 = 1 .

<h3>How to find the standard equation of a hyperbola</h3>

In this problem we must determine the equation of the hyperbola in its <em>standard</em> form from the coordinates of the foci and a <em>general</em> equation of a circle. Based on the location of the foci, we see that the axis of symmetry of the hyperbola is parallel to the x-axis. Besides, the center of the hyperbola is the midpoint of the line segment with the foci as endpoints:

(h, k) = 0.5 · (- 1, 2) + 0.5 · (5, 2)

(h, k) = (2, 2)

To determine whether it is possible that the vertices are endpoints of the diameter of the circle, we proceed to modify the <em>general</em> equation of the circle into its <em>standard</em> form.

If the vertices of the hyperbola are endpoints of the diameter of the circle, then the center of the circle must be the midpoint of the line segment. By algebra we find that:

x² + y² - 4 · x - 4 · y + 4= 0​

(x² - 4 · x + 4) + (y² - 4 · y + 4) = 4

(x - 2)² + (y - 2)² = 2²

The center of the circle is the midpoint of the line segment. Now we proceed to determine the vertices of the hyperbola:

V₁(x, y) = (0, 2), V₂(x, y) = (4, 2)

And the distance from the center to any of the vertices is 2 (<em>semi-major</em> distance, a) and the semi-minor distance is:

b = √(c² - a²)

b = √(3² - 2²)

b = √5

Therefore, the <em>standard</em> form of the equation of the hyperbola that satisfies all conditions is (x - 2)²/4 - (y - 2)²/5 = 1 .

To learn more on hyperbolae: brainly.com/question/27799190

#SPJ1

5 0
1 year ago
Simplify 5(a - <br> b. 6(a <br> b. - 7(a - 2b)
Elan Coil [88]
Not sure what you're asking. are you wanting to solve 5 ( a - b), where b equals those two things listed below? If that's the case, I can definitely help. If not, please clarify.
6 0
3 years ago
Find (5.2 x 107)(5 x 108) (3.2 x 106)(5 x 105) , expressed in scientific notation. A) 1.625 x 104 B) 1.625 x 105 C) 8.125 x 104
olga nikolaevna [1]

Answer:

I think it is A) 1.625 x 10^4

4 0
3 years ago
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