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nikklg [1K]
3 years ago
12

What is the sum of 1/8 + 5/16+ 1/8?

Mathematics
1 answer:
san4es73 [151]3 years ago
7 0

Answer:

9/16

Step-by-step explanation:

1) convert 1/8 into 2/16 so denominator are the same

2) then you just add the fractions

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Y=−2x+4 <br> exponential or not? if exponential growth or decay
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Which answers are
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A and B are the answers

Step-by-step explanation:

3^9 / 3^9 = 1

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Show that if you pick three marbles from a jar containing only blue and red marbles, you must get a pair of blue or a pair of re
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On friday ,a museum had 185 visitors.on saturday,there were twice as many visitors as Friday.On Sunday, 50 fewer people visited
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This is the equation
185+185(2)+185-50
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5 0
4 years ago
Read 2 more answers
The alkalinity level of water specimens collected from the Han River in Seoul, Korea, has a mean of 50 milligrams per liter and
Sati [7]

Answer:

a) 94.06% probability that a water specimen collected from the river has an alkalinity level exceeding 45 milligrams per liter.

b) 94.06% probability that a water specimen collected from the river has an alkalinity level below 55 milligrams per liter.

c) 50.98% probability that a water specimen collected from the river has an alkalinity level between 48 and 52 milligrams per liter.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 50, \sigma = 3.2

a. exceeding 45 milligrams per liter.

This probability is 1 subtracted by the pvalue of Z when X = 45. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{45 - 50}{3.2}

Z = -1.56

Z = -1.56 has a pvalue of 0.0594.

1 - 0.0594 = 0.9406

94.06% probability that a water specimen collected from the river has an alkalinity level exceeding 45 milligrams per liter.

b. below 55 milligrams per liter.

This probability is the pvalue of Z when X = 55.

Z = \frac{X - \mu}{\sigma}

Z = \frac{55 - 50}{3.2}

Z = 1.56

Z = 1.56 has a pvalue of 0.9604.

94.06% probability that a water specimen collected from the river has an alkalinity level below 55 milligrams per liter.

c. between 48 and 52 milligrams per liter.

This is the pvalue of Z when X = 52 subtracted by the pvalue of Z when X = 48. So

X = 52

Z = \frac{X - \mu}{\sigma}

Z = \frac{52 - 50}{3.2}

Z = 0.69

Z = 0.69 has a pvalue of 0.7549

X = 48

Z = \frac{X - \mu}{\sigma}

Z = \frac{48 - 50}{3.2}

Z = -0.69

Z = -0.69 has a pvalue of 0.2451

0.7549 - 0.2451 = 0.5098

50.98% probability that a water specimen collected from the river has an alkalinity level between 48 and 52 milligrams per liter.

4 0
3 years ago
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