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Ann [662]
4 years ago
5

Sodium-24 has a half-life of 15 hours. how many grams of a 900 g sample will remain after 90 hours

Mathematics
1 answer:
raketka [301]4 years ago
4 0

Answer: Option 'B' is correct.

Step-by-step explanation:

Let the initial concentration be

N_0=900\ g

Let concentration after t= 90 hours be N

Since we have given that Sodium-24 has a half life of 15 hours i.e.

t_{\frac{1}{2}}=15

So, According to question,

\text{ Number of half lives }=\frac{t}{t_{\frac{1}{2}}}\\\\\text{ Number of half lives }=\frac{90}{15}\\\\\text{ Number of half lives }=6

As we know that

\frac{N}{N_0}=(\frac{1}{2})^n\\\\N=N_0\times (\frac{1}{2})^n\\\\N=900\times (\frac{1}{2})^6\\\\N=\frac{900}{64}\\\\N=14.0625\ g

Hence, Option 'B' is correct.

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Question 26 pleaseee
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Answer:

The inequality is 55+10x\leq 105

The greatest length of time Jeremy can rent the jet ski is 5 and Jeremy can rent maximum of 135 minutes.

Step-by-step explanation:

Given: Cost of first hour rent of jet ski is $55

          Cost of each additional 15 minutes of jet ski is $10

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Assuming the number of additional 15-minutes increment be "x"

Jeremy´s total spending would be first hour rental fees and additional charges for each 15-minutes of jet ski.

Lets put up an expression for total spending of Jeremy.

\$55+ \$ 10\times x

We also know that Jeremy can not spend more than $105

∴ Putting up the total spending of Jeremy in an inequality.

\$ 55+\$10x\leq \$ 105

Now solving the inequality to find the greatest number of time Jeremy can rent the jet ski,

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Subtracting both side by 55

⇒ \$ 10x\leq \$50

Dividing both side by 10

⇒x\leq \frac{50}{10}

∴ x\leq 5

Therefore, Jeremy can rent for 60\ minutes + 5\times 15\\= 60\ minutes + 75= 135\ minutes

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3 years ago
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Answer:

(C) 10 units

Step-by-step explanation:

It is given that EFGH is a rhombus and EG = 16 and FH = 12.

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