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bearhunter [10]
3 years ago
10

Divide m^2n^3/p^3 by mp/n^2

Mathematics
2 answers:
Andreas93 [3]3 years ago
5 0

Answer:

Dividing \frac{m^2n^3}{p^3}  by \frac{mp}{n^2} is mn^5p^{-4}

Step-by-step explanation:

Divide  \frac{m^2n^3}{p^3}  by \frac{mp}{n^2}

Solution :

We divide first expression by another,

=\frac{\frac{m^2n^3}{p^3}}{\frac{mp}{n^2}}

=\frac{m^2n^3}{p^3}\times \frac{n^2}{mp}

=\frac{m^2n^5}{mp^4}

=m^{2-1}n^5p^{-4}

=mn^5p^{-4}

Therefore, Dividing \frac{m^2n^3}{p^3}  by \frac{mp}{n^2} is mn^5p^{-4}

andriy [413]3 years ago
4 0
M^2n^3
----------
  p^3                m^2n^3            n^2          mn^5
--------------- =  -------------- * ---------- = -------------
  mp                     p^3            mp              p^4
-------
  n^2

hope this will help you 
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