All categories

3 years ago

What is 6,4 rounded to the nearest whole number

Mathematics

1 answer:

Aleks04 [339]3 years ago

6 0

6.4 rounded to the nearest whole number will be 6.

if the decimal was 5 or larger, it would’ve been 7.

You might be interested in

Completely simplified the expression for x plus 10 plus 6 x plus 2 x by combining like terms into your answer in the box.

siniylev [52]

We can first turn the text into a proper formula:

x plus 10 plus 6 x plus 2 x

x+10+6x+2x

The like terms are the numbers with

We can then put the like terms together to continue the calculation:

x+6x+2x+10

=9x + 10

Therefore, the answer is 9x + 10.

Hope it helps!

7 0

3 years ago

Read 2 more answers

When solving problems with units we sometimes ____ to get the units the same.

laiz [17]

Convert is your answer .-.

4 0

3 years ago

Read 2 more answers

I need help please I’ll give you five stars!

alisha [4.7K]

The answer is no i do not agree

6 0

2 years ago

13 less than 8 times a number is the same as the number plus 1

aliya0001 [1]

8x - 13 = x + 1
Solve for x
Add 13
8x = x + 14
Subtract x
7x = 14, x = 2
Answer: the number is 2

7 0

2 years ago

In analyzing the city and highway fuel efficiencies of many cars and trucks, the mean difference in fuel efficiencies for the 60

Olegator [25]

Answer:

$7.38-1.96\frac{2.51}{\sqrt{601}}=7.18$

$7.38+1.96\frac{2.51}{\sqrt{601}}=7.58$

For this case the confidence interval is given by :

$7.18 \leq \mu \leq 7.58$

Step-by-step explanation:

Data provided

$\bar X=7.38$ represent the sample mean for the fuel efficiencies

$\mu$ population mean

s=2.51 represent the sample standard deviation

n=601 represent the sample size

Confidence interval

The formula for the confidence interval of the true mean is given by:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom for this case is given by:

$df=n-1=601-1=600$

The Confidence level for this case is 0.95 or 95%, and the significance level $\alpha=0.05$ and $\alpha/2 =0.025$ and the critical value is given by $t_{\alpha/2}=1.96$

Replcing into the formula for the confidence interval is given by:

$7.38-1.96\frac{2.51}{\sqrt{601}}=7.18$

$7.38+1.96\frac{2.51}{\sqrt{601}}=7.58$

For this case the confidence interval is given by :

$7.18 \leq \mu \leq 7.58$

8 0

3 years ago