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kvv77 [185]
3 years ago
5

Can an object have zero velocity but non-zero acceleration? Can it have zero acceleration and nonzero velocity? Please support y

our answer.
Mathematics
1 answer:
ivann1987 [24]3 years ago
6 0
Both can be true.
The first can be true in the cause of an object being thrown up, for example. If I throw a baseball up into the air, it has a constant downward acceleration of 9.81 m/s^2 (g), but when it reaches the top of the arc, it has zero velocity.
The second can be true for an object not under the influence of any net outside force. You may have seen Newton's first law before:
"Every object in a state of uniform motion tends to remain in that state of motion unless an external force is applied to it."

If an item is floating through a volume of space with no gravity effects and no air resistance, it will continue to move at a constant velocity.

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Write the related facts for the set of numbers 2,9,18
Salsk061 [2.6K]

Answer:

18 is divisible by both 2 and 9, you can multiply 9 by 2 to get 18, and 18 is a multiple of both of those numbers

Step-by-step explanation:


5 0
3 years ago
1/2x + 1/3y = 3
masha68 [24]
1/2x + 1/3y = 3

Well, because every answer choice isn't in fraction form, simply multiply EVERYTHING by 6 :)

6(1/2x + 1/3y = 3)

Simplify.

3x + 2y = 18

So, our LAST answer choice is correct.

~Hope I helped!~
7 0
3 years ago
Read 2 more answers
The measure of an angle formed by two secants intersecting outside the circle equals
sineoko [7]
When two secants (Line A + B<span> and </span>Line C + D) intersect, they form an angle (∠y) equal to:
      ½ (the larger intercepted arc minus<span> the smaller intercepted arc)
</span>
(Make sure to look at the graphic I posted)


5 0
4 years ago
What would be the first step to this system of equations?
blagie [28]

The first step to apply using the elimination method is by multiplying the whole value of equation 1 by 3/2.

\begin{gathered} (2x+3y=5\text{ )}\times\frac{3}{2} \\ -3x+2y=-14 \\ 3x+\frac{9}{2}y=\frac{15}{2} \\ -3x+2y=-14 \\ \frac{9}{2}y+2y=\frac{15}{2}-14 \\ \frac{9y+4y}{2}=\frac{15-28}{2} \\ \frac{13y}{2}=\frac{-13}{2} \\ 26y=-26 \\ y=-1 \\ -3x+2(-1)=-14 \\ -3x-2=-14 \\ -3x=-14+2 \\ -3x=-12 \\ x=\frac{-12}{-3} \\ x=4 \end{gathered}

7 0
1 year ago
HELP ME PLEASE I NEED HELP ASAP
Nat2105 [25]

Answer:

82 i think

Step-by-step explanation:

hope this helps :3

if it did pls mark brainliest

im so sorry if its wrong

6 0
3 years ago
Read 2 more answers
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