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3 years ago

PLEASE HELP!! URGENT!!! PLEASE!

2 answers:

8 0

1. 11-bc if u square it and then square root it would just be that number bc if u square it it is just 11*11 and the square root of that would be 11.
2. 5.5
3. 2/3
4. 12-u r trying to figure out what times what equals 144, so 12
5. 8

valina [46]3 years ago

3 0

Answer:

1. 11^2

2. 5.5^2

3. $\sqrt \frac{4}{9}$

4. 12^2

5. 8^2

Step-by-step explanation:

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Gwar [14]

Answer:

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3 years ago

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Fynjy0 [20]

Answer:

the one solution is -20

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Mrs Harris needs 2 and3/4 meters of material to make a dress. How many similar dresses could she make from a roll of material, 3

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3 years ago

Angle A and Angle B are supplementary. Angle A has a measure of 3x - 6 and Angle B has a measure of 54. What is the value of x?

Anni [7]

Answer:

44 degrees

Step-by-step explanation:

Since they are supplementary, they add up to 180. This means that

3x - 6 + 54 = 180

Solving,

3x + 48 = 180

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3x = 132

divide both sides by 3

x = 44 degrees

8 0

3 years ago

Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse

Drupady [299]

Answer:

$a'(d) = \frac{d}{5} + \frac{3}{5}$

$a(a'(d)) = a'(a(d)) = d$

Step-by-step explanation:

Given

$a(d) = 5d - 3$

Solving (a): Write as inverse function

$a(d) = 5d - 3$

Represent a(d) as y

$y = 5d - 3$

Swap positions of d and y

$d = 5y - 3$

Make y the subject

$5y = d + 3$

$y = \frac{d}{5} + \frac{3}{5}$

Replace y with a'(d)

$a'(d) = \frac{d}{5} + \frac{3}{5}$

Prove that a(d) and a'(d) are inverse functions

$a'(d) = \frac{d}{5} + \frac{3}{5}$ and $a(d) = 5d - 3$

To do this, we prove that:

$a(a'(d)) = a'(a(d)) = d$

Solving for $a(a'(d))$

$a(a'(d)) = a(\frac{d}{5} + \frac{3}{5})$

Substitute $\frac{d}{5} + \frac{3}{5}$ for d in $a(d) = 5d - 3$

$a(a'(d)) = 5(\frac{d}{5} + \frac{3}{5}) - 3$

$a(a'(d)) = \frac{5d}{5} + \frac{15}{5} - 3$

$a(a'(d)) = d + 3 - 3$

$a(a'(d)) = d$

Solving for: $a'(a(d))$

$a'(a(d)) = a'(5d - 3)$

Substitute 5d - 3 for d in $a'(d) = \frac{d}{5} + \frac{3}{5}$

$a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}$

Add fractions

$a'(a(d)) = \frac{5d - 3+3}{5}$

$a'(a(d)) = \frac{5d}{5}$

$a'(a(d)) = d$

Hence:

$a(a'(d)) = a'(a(d)) = d$

7 0

3 years ago