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a_sh-v [17]
3 years ago
13

What value of n makes this equation true? n-2.3=17

Mathematics
2 answers:
MA_775_DIABLO [31]3 years ago
7 0

n-2.3=17

The first step is to "isolate" your variable (n). To isolate your variable means to make it so that there is just n on one side of the equal sign.

To do that, you must use inverse operations and add 2.3 to each side of the equation:

n-2.3=17

+2.3     +2.3

n=17+2.3

The next step is to just simplify:

n=17+2.3

n=19.3

Hope this helps!!!

juin [17]3 years ago
4 0

Hey there!

n-2.3= 17

Add 2.3 to both sides. (always do the inverse)

n=19.3

I hope this helps!

~kaikers

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cesar left the college traveling 12 mph. Then, 4 hours later, Gabriel left traveling the same direction at 24 mph. How long will
Sloan [31]

Answer:

Step-by-step explanation:

Given that cesar left the college traveling 12 mph. Then, 4 hours later, Gabriel left traveling the same direction at 24 mph.

Before Gabriel started Cesar would have travelled for 4 hours

So distance travelled by Cesar in 4 hours =4(12) =48 miles

Thus Cesar is ahead of Gabriel by 48 miles

Difference of speed =(24-12) =12 mph

So to catch Cesar time required = 48/difference in speed

= 4 hours

It will take 4 hours.

8 0
3 years ago
Assume that y varies directly with x. If y = -5 when
steposvetlana [31]

Answer:

Thus, the value of x = -36 when y = 15

Step-by-step explanation:

We know that if y varies directly with x, we can express the relationship such as

y ∝ x

y = kx

k = y/x

where 'k' is called constant of variation.

Given

y = -5

x = 12

Using the equation

k = y/x = -5/12

Thus, the value of k = -5/12

Finding x when y = 15

y = 15

k = -5/12

substituting y = 15 and k = -5/12 in the equation

y = kx

15 = -5/12 (x)

15×12 = -5x

180 = -5x

divding both sides by -5

-5x/-5 = 180/-5

x = -36

Thus, the value of x = -36 when y = 15

8 0
3 years ago
Your plan was to be on the road by 9 A.M. but you did not leave the garage until 10 A.M. You then drove with the cruise control
Wittaler [7]

Answer:

The average speed over the time interval from 9 A.M. to noon was of 33.33 mph.

Step-by-step explanation:

The average speed is given by the following equation:

v = \frac{d}{t}

From 10A.M. to noon.

You traveled at 50mph during 2 hours. So how long you traveled?

50 = \frac{d}{2}

d = 50*2

d = 100

You traveled 100 miles.

What was your average speed over the time interval from 9 A.M. to noon

From 9 A.M. to 10 A.M, you did not travel.

From 10 P.M. to noon, 100 miles.

So 100 miles during 3 hours.

v = \frac{d}{t} = \frac{100}{3} = 33.33

The average speed over the time interval from 9 A.M. to noon was of 33.33 mph.

8 0
3 years ago
X*2+1=10 then x=? Tell me the value of x
Trava [24]

Answer:

<h2>4.5</h2>

Step-by-step explanation:

x \times 2 + 1 = 10

2x +  1 = 10

Move constant to R.H.S and change its sign

2x = 10 - 1

Subtract the numbers

2x = 9

Divide both sides of the equation by 2

\frac{2x}{2}  =  \frac{9}{2}

Calculate

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Hope this helps..

Best regards!!

6 0
2 years ago
Which equation demonstrates the additive identity property?
Mrrafil [7]

Answer:

Step-by-step explanation:

Solve for o in the equation (7 + 4) + (7 - 41) = 14©(7 + 4) + 0 = 7 + 41o(7 + 4)(1) = 7 + 41o(7 + 41) + ( - 7 - 41) = 0

We first need to simplify the expression removing parentheses

Simplify 41o(7 + 4): Distribute the 41o to each term in (7+4)

41o * 7 = (41 * 7)o = 287o 41o * 4 = (41 * 4)o = 164o

Our Total expanded term is 287o + 164o

Simplify 41o(7 + 41): Distribute the 41o to each term in (7+41)

41o * 7 = (41 * 7)o = 287o 41o * 41 = (41 * 41)o = 1681o

Our Total expanded term is 287o + 1681o

Our updated term to work with is (7 + 4) + (7 - 41) = 14©(7 + 4) + 0 = 7 + 287o + 164o(1) = 7 + 287o + 1681o + ( - 7 - 41) = 0

We first need to simplify the expression removing parentheses

Simplify 164o(1): Distribute the 164o to each term in (1)

164o * 1 = (164 * 1)o = 164o Our Total expanded term is 164o

Our updated term to work with is (7 + 4) + (7 - 41) = 14©(7 + 4) + 0 = 7 + 287o + 164o = 7 + 287o + 1681o + ( - 7 - 41) = 0

Step 1: Group variables: We need to group our variables (7 and 14©(7. To do that, we subtract 14©(7 from both sides (7 - 14©(7 = 14©(7 - 14©(7

Step 2: Cancel 14©(7 on the right side: 0o = 0 Step 3: Divide each side of the equation by 0

5 0
3 years ago
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