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4 years ago

What is the prime factorization of 64?

Mathematics

2 answers:

Liula [17]4 years ago

8 0

For this we just need to keep dividing 64 until we are left with just the prime numbers:

64
=2*32
=2*2*16
=2*2*2*8
=2*2*2*2*4
=2*2*2*2*2*2

Therefore, 64 = 2^6

son4ous [18]4 years ago

5 0

Start with lowest prime numbers
64/2,
2 32/2,
2 2 16/2,
2 2 2 8/2,
2 2 2 2 4/2,
2 to the 6th
check by multiplying back
2 x 2 x 2 x 2 x 2 x 2= 64

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3 years ago

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4 years ago

Given that P=x+y Find P when: x=−6 and y=−7 what is p?

m_a_m_a [10]

Answer:

P = -13

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Step-by-step explanation:

Step 1: Define

P = x + y

x = -6

y = -7

Step 2: Evaluate

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3 years ago

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bogdanovich [222]

Answer:

$\displaystyle \int {84} \, dx = 84x + C$

General Formulas and Concepts:

Calculus

Integration

Integrals
Definite/Indefinite Integrals
Integration Constant C

Integration Rule [Reverse Power Rule]: $\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C$

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle \int {84} \, dx$

Step 2: Integrate

[Integral] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle \int {84} \, dx = 84\int {} \, dx$
[Integral] Reverse Power Rule: $\displaystyle \int {84} \, dx = 84x + C$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integrations

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3 years ago