Answer:
0
Step-by-step explanation:
∫ sin²(x) cos(x) dx
If u = sin(x), then du = cos(x) dx.
∫ u² du
⅓ u³ + C
⅓ sin³(x) + C
Evaluate between x=0 and x=π.
⅓ sin³(π) − ⅓ sin³(0)
0
Answer:
C. Both (1, 11) and (-1, -5)
Step-by-step explanation:
The missing options are:
<em>
A. Only (1, 11)
</em>
<em>B. Only (-1, -5) </em>
<em>C. Both (1, 11) and (-1, -5)
</em>
<em>D. Neither </em>
To check if an ordered pair is a solution of an equation, replace one variable into the equation an calculate the other one.
Replacing x = 1, we get:
y = 8(1) + 3
y = 11
then (1, 11) is a solution
Replacing x = -1, we get:
y = 8(-1) + 3
y = -5
then (-1, -5) is a solution
You may find it easiest if you convert all the fractions to decimal form:
5.433...
5.166...
5.756
Now reorder these from smallest to largest.
Note: I had to guess that by "68,90," you actually meant "68/90."
The area of a square is its side length squared. So the side length of the square squared is 42, so the side length of the square is sqrt(42). The perimeter of the square is 4 times the side length, or 4sqrt(42), which is approximately 25.92.
Answer:
another way to write this is 1:3
