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3 years ago

Math help please? <3

Mathematics

1 answer:

ipn [44]3 years ago

3 0

A linear equation cannot be used.
because 60/1 isn't equal to 70/5 and isn't equal to 80/20 and so on.

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The difference of 10 and the product of n and 2 is 4 which operation models this

vagabundo [1.1K]

Answer:

10 - 2n - 4

Step-by-step explanation:

The product of n and 2 is 2n.

Then 10 - 2n is the difference of 10 and the product of n and 2.

In conclusion, we have:

10 - 2n - 4

3 0

3 years ago

Consider the linear transformation T from V = P2 to W = P2 given by T(a0 + a1t + a2t2) = (2a0 + 3a1 + 3a2) + (6a0 + 4a1 + 4a2)t

Svet_ta [14]

Answer:

$[T]EE=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]$

Step-by-step explanation:

First we start by finding the dimension of the matrix [T]EE

The dimension is : Dim (W) x Dim (V) = 3 x 3

Because the dimension of P2 is the number of vectors in any basis of P2 and that number is 3

Then, we are looking for a 3 x 3 matrix.

To find [T]EE we must transform the vectors of the basis E and then that result express it in terms of basis E using coordinates and putting them into columns. The order in which we transform the vectors of basis E is very important.

The first vector of basis E is e1(t) = 1

We calculate T[e1(t)] = T(1)

In the equation : 1 = a0

$T(1)=(2.1+3.0+3.0)+(6.1+4.0+4.0)t+(-2.1+3.0+4.0)t^{2}=2+6t-2t^{2}$

$[T(e1)]E=\left[\begin{array}{c}2&6&-2\\\end{array}\right]$

And that is the first column of [T]EE

The second vector of basis E is e2(t) = t

We calculate T[e2(t)] = T(t)

in the equation : 1 = a1

$T(t)=(2.0+3.1+3.0)+(6.0+4.1+4.0)t+(-2.0+3.1+4.0)t^{2}=3+4t+3t^{2}$

$[T(e2)]E=\left[\begin{array}{c}3&4&3\\\end{array}\right]$

Finally, the third vector of basis E is $e3(t)=t^{2}$

$T[e3(t)]=T(t^{2})$

in the equation : a2 = 1

$T(t^{2})=(2.0+3.0+3.1)+(6.0+4.0+4.1)t+(-2.0+3.0+4.1)t^{2}=3+4t+4t^{2}$

Then

$[T(t^{2})]E=\left[\begin{array}{c}3&4&4\\\end{array}\right]$

And that is the third column of [T]EE

Let's write our matrix

$[T]EE=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]$

T(X) = AX

Where T(X) is to apply the transformation T to a vector of P2,A is the matrix [T]EE and X is the vector of coordinates in basis E of a vector from P2

For example, if X is the vector of coordinates from e1(t) = 1

$X=\left[\begin{array}{c}1&0&0\\\end{array}\right]$

$AX=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]\left[\begin{array}{c}1&0&0\\\end{array}\right]=\left[\begin{array}{c}2&6&-2\\\end{array}\right]$

Applying the coordinates 2,6 and -2 to the basis E we obtain

$2+6t-2t^{2}$

That was the original result of T[e1(t)]

8 0

3 years ago

Given h(x) = |x+3| -5

statuscvo [17]

Answer:

The parent function f(x) is equal to $f\left(x\right)=\left|x\right|$

The translations is 3 units to the left and 5 units down

Step-by-step explanation:

we have

$h\left(x\right)=\left|x+3\right|-5$

The vertex of the function h(x) is the point (-3,-5)

we know that the parent function f(x) is equal to

$f\left(x\right)=\left|x\right|$

The vertex of the function f(x) is the point (0,0)

The rule of the transformation of f(x) to h(x) is equal to

(x,y) -----> (x-3,y-5)

That means ----> The translations is 3 units to the left and 5 units down

4 0

4 years ago

First let's go on a trip you have $10,000 US to take with you look up the current exchange rate of US dollars to see dollars wha

deff fn [24]

So the exchange rate from one US dollar to a Canadian dollar is equal to 1.30 Canadian dollars. So in this current situation if you swapped all of your US dollars for Canadian dollars you would have $13000 Canadian dollars

8 0

3 years ago

Im leaving brainly first to this question gets brainliest i giving away all my points so i have only have one question

ehidna [41]

Answer:

gta v

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers