Answer:
Step-by-step explanation:
Question
Find the perimeter of a triangle with vertices A(2,5) B(2,-2) C(5,-2). Round your answer to the nearest tenth and show your work.
perimeter of a triangle = AB+AC+BC
Using the distance formula
AB = sqrt(-2-5)²+(2-2)²
AB = sqrt(-7)²
AB =sqrt(49)
AB =7
BC = sqrt(-2+2)²+(2-5)²
BC = sqrt(0+3²)
BC =sqrt(9)
BC =3
AC= sqrt(-2-5)²+(2-5)²
AC= sqrt(-7)²+3²
AC =sqrt(49+9)
AC =sqrt58
Perimeter = 10+sqrt58
<span> The surface area of a right prism can be calculated using the following formula: SA 5 2B 1 hP, where B is the area of the base, h is the height of the prism, and P is the perimeter of the base. The lateral area of a figure is the area of the non-base faces only.</span>
Answer:
sin^2α
Step-by-step explanation:
I will just pose x instead of alpha here to make things simpler
we know that sin^2x = 1 - cos^2x so...
we can rewrite using trigonometric identities (tan = sin/cos)...
Cross multiply:
2.5 ft x 16.5 ft = 41.25 ft
now divide:
41.25 / 8.25 = 5
L = 5 feet
Answer:
+89
Step-by-step explanation:
