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3 years ago

How to write 1/3, 1/5 as an a common denominator as an equivalent fraction

Mathematics

1 answer:

Anni [7]3 years ago

6 0

Answer:

Step-by-step explanation:

$\dfrac{1}{3}\\\\\text{List multiples of 3:}\ 0,\ 3,\ 6,\ 9,\ 12,\ \boxed{15},\ 18,\ 21,\ ...\\\\\dfrac{1}{5}\\\\\text{List multiples of 5:}\ 0,\ 5,\ 10,\ \boxed{15},\ 20,\ 25,\ ...\\\\\text{The common denominator is 15.}\\\\\dfrac{1}{3}=\dfrac{1\cdot5}{3\cdot5}=\dfrac{5}{15}\\\\\dfrac{1}{5}=\dfrac{1\cdot3}{5\cdot3}=\dfrac{3}{15}$

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If the discriminant of a quadratic equation is equal to -8, which statement describes the roots'

OlgaM077 [116]

If the discriminant of a quadratic equation is equal to -8, there are two complex roots.

<h3>Discriminant of a quadratic equation</h3>

The discriminant is used to determine the nature of quadratic equations.

The formula for calculating discriminant is given as:

D = b^2 - 4ac

If the discriminant is negative, it means that the nature of the solution will be a complex number.

Hence if the discriminant of a quadratic equation is equal to -8, there are two complex roots.

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3 years ago

How do I find out the answer for this: 30! If you can solve this you get a lot of points!!!

charle [14.2K]

30! equals 2.6525286e+32
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3 years ago

75 is what percent of 1507

seraphim [82]

Answer:

4.9767750498%

Step-by-step explanation:

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3 years ago

Read 2 more answers

Solve for y<br><img src="https://tex.z-dn.net/?f=3x%20-%20y%20%3D%20%20-%202y" id="TexFormula1" title="3x - y = - 2y" alt="3x -

SVETLANKA909090 [29]

Step 1: Subtract $3x$ from both sides. Leaving us with $-y = -3x -2y$

Step 2: Add $2y$ to both sides. Leaving us with $y = -3x$

So, your answer would be y = -3x

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3 years ago

Find all solutions <br> 36x²+12x=0

FromTheMoon [43]

Answer:

x = -1/3 or 0

Step-by-step explanation:

Given equation:

$36x^{2} + 12x = 0$

We can factor 12x on the L.H.S since 12x is divisible by 36x² and 12x.

$\implies 36x^{2} + 12x = 0$

$\implies 12x(3x + 1) = 0$

This can lead to two solutions. I have listed them below!

<h2>Solution 1:</h2>

Divide 12x on both sides to open the parentheses.

$\implies 12x(3x + 1) = 0$

$\implies \dfrac{12x(3x + 1)}{12} = \dfrac{0}{12}$

<em>Note: zero divided by any non-zero number is 0.</em>

$\implies \dfrac{12x(3x + 1)}{12} = \dfrac{0}{12}$

$\implies 3x + 1 = 0$

Isolate 3x on one side of the equation.

$\implies 3x + 1 = 0$

$\implies 3x = 0 - 1$

$\implies 3x = -1$

Divide 3 both sides to determine the value of x.

$\implies 3x = -1$

$\implies \dfrac{3x}{3} = \dfrac{-1}{3}$

$\implies \boxed{x = \dfrac{-1}{3}}$

<h2>Solution 2:</h2>

Divide (3x + 1) on both sides to isolate 12x.

$\implies 12x(3x + 1) = 0$

$\implies \dfrac{12x(3x + 1)}{(3x + 1)} = \dfrac{0}{(3x + 1)}$

<em>Note: zero divided by any non-zero number is 0.</em>

$\implies \dfrac{12x(3x + 1)}{(3x + 1)} = \dfrac{0}{(3x + 1)}$

$\implies 12x = 0$

Divide 12 both sides to determine the value of x.

$\implies 12x = 0$

$\implies \dfrac{12x}{12} = \dfrac{0}{12}$

$\implies \boxed{x = 0}$

Therefore, the solutions for x are -1/3 or 0.

Learn more about this topic: brainly.com/question/295675

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2 years ago

Read 2 more answers