Answer:
d(x) = √[(x - 2)² + (3x - 1)²]
Step-by-step explanation:
The distance between two points with coordinates (x₁, y₁) and (x₂, y₂) is given as
d = √[(x₂ - x₁)² + (y₂ - y₁)²]
So, the distance between point (2,0) and a point (x,y)
d = √[(x - 2)² + (y - 0)²]
d = √[(x - 2)² + (y)²]
But the point (x,y) is on the line y = 3x - 1
We can substitute for y in the distance between points equation.
d(x) = √[(x - 2)² + (3x - 1)²]
QED!
The height of the ramp above the ground from its highest end is 7.9 inches.
<h3>What is height?</h3>
Height is the vertical distance between two points.
To calculate the height of the ramp above the ground, we use the formula below.
Formula:
- h = Lsin∅............. Equation 1
Where:
- h = Height of the ramp above the ground
- L = Length of the fiberboard
- ∅ = Angle of elevation from the ground
From the question,
Given:
Substitute these values into equation 1
- h = 27×sin17°
- h = 7.89
- h ≈ 7.9 inches
Hence, the height of the ramp above the ground is 7.9 inches.
Learn more about height here: brainly.com/question/23144757
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Answer:
35-=13 boxes ; 65-9 boxes
Step-by-step explanation:
35 x X+ 65 (22-x)=1040
35x+1430-65x=1040
1430-30x=1040
30x=390
x =390/30=13
6a. 1 - 2sin(x)² - 2cos(x)² = 1 - 2(sin(x)² +cos(x)²) = 1 - 2·1 = -1
6c. tan(x) + sin(x)/cos(x) = tan(x) + tan(x) = 2tan(x)
6e. 3sin(x) + tan(x)cos(x) = 3sin(x) + (sin(x)/cos(x))cos(x) = 3sin(x) +sin(x) = 4sin(x)
6g. 1 - cos(x)²tan(x)² = 1 - cos(x)²·(sin(x)²)/cos(x)²) = 1 -sin(x)² = cos(x)²
