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3 years ago

Question 15

Mathematics

1 answer:

solniwko [45]3 years ago

7 0

The answer fam is......... 3x – 4y = 4

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Which expression can be used to represent the phrase Lamar decreased his collection of cards by seven

jenyasd209 [6]

Answer:

$x-7$

Step-by-step explanation:

Let

x------> Lamar's collection of cards

The algebraic expression of the phrase "Lamar decreased his collection of cards by seven" is equal to subtract the number seven from Lamar's collection of cards

$x-7$

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3 years ago

cindy made 5/6 of a quart of hot chocolate. Each mug holds 1/6 of a quart. How many mugs will Cindy be able to fill?

Ostrovityanka [42]

The problem is really asking 5/6 divides by 1/6. This yields 5. Hope this helps!

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3 years ago

Whoever answer is the best gets brainlist

Otrada [13]

The answer is 18^8 because u add exponents

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4 years ago

Read 2 more answers

If a rectangle has an area of 2x^2+7x+3 find the perimeter

nikdorinn [45]

Perimeter of a rectangle = 6x + 8

Solution:

Given area of a rectangle = $2x^2+7x+3$

Let us first factor the given polynomial.

$2x^2+7x+3=2x^2+x+6x+3$

$=(2x^2+x)+(6x+3)$

Taking out common terms in the above expression

$=x(2x+1)+3(2x+1)$

Taking out common term $2x+1$ in the above expression

$=(2x+1)(x+3)$

$2x^2+7x+3=(2x+1)(x+3)$

Area of a rectangle = l × b

Therefore, $l=2x+1$ and $b=x+3$

Perimeter of a rectangle = 2(l + b)

$=2[(2x+1)+(x+3)]$

$=2(2x+1+x+3)$

$=2(3x+4)$

$=6x+8$

The answer is same if you take l = x + 3 and b = 2x + 1.

Hence, perimeter of a rectangle = 6x + 8.

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3 years ago

If A and B are independent events, P(A) = 0.25, and P(B) = 0.45, find the probabilities below. (Enter your answers to four decim

Kamila [148]

we are given two probabilities of two events: P(A) = 0.25, and P(B) = 0.45. we are asked to determine P(A ∩ B) which has a formula of P(A) * P(B) equal to 0.25 *0.45 equal to 0.1125. P(A ∪ B) has a formula of P(A) + P(B) equal to 0.70. (c) P(A | B) is 0.25/0.45 equal to 0.56. (d) P(Ac ∪ Bc) is equal to (1-0.25)*(1-0.45) equal to 0.4125.

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3 years ago