All categories

2 years ago

Question 15

Mathematics

1 answer:

solniwko [45]2 years ago

7 0

The answer fam is......... 3x – 4y = 4

You might be interested in

68% of the tickets sold at a water park were child tickets. If the park sold 50 tickets in all, how many child tickets did it se

Mnenie [13.5K]

Answer:

$\boxed{\bf\: The \: park \: sold \boxed{ 34{}} \: child \: tickets.}$

Step-by-step explanation:

Given:

Percentage of Tickets sold at a water park - 68%

The Number of Tickets if the park sold in all - 50

To Find:

The Number of child tickets the park sold.

Solution:

We know that 68% equals to 68/100.

Step 1: Multiply 68/100 by 50 which is the number of tickets the park sold :-

$\sf \: = \: \cfrac{68}{100} \times 50$

Note:The Simplified form of 68/100 * 50 would be the answer to this question.

Step 2: Cancel One zero of 50 and one zero of 100,That is:-

$\sf = \cfrac{68}{ 10\cancel0} \times 5 \cancel0$

Results to,

$\sf = \cfrac{68}{10} \times 5$

Step 3: Cancel 5 and 10, That is:-

$\sf = \cfrac{68}{ \cancel{10 }} \times \cancel5$

Results to,

$\sf =\: \cfrac{68}{2} \times 1$

$\sf = \cfrac{68}{2}$

Step 4: Cancel 68 and 2, That is:-

$\sf =\: \cfrac{ \cancel{68}}{ \cancel2}$

Results to,

$\sf = \cfrac{34}{1}$

$\sf = 34$

34 is the result.

Hence,

$\underline{ \rm \: The \: park \: sold \: \bold{ 34 } \: child \: tickets.}$

________________________________

I hope this helps!

Let me know if you have any questions.I am joyous to help!

6 0

2 years ago

Please tell me if I was right.

Gennadij [26K]

Im pretty sure you are i have done this question before and im pretty sure thats what i put and i got it right. plus just go with your gut

8 0

3 years ago

I don’t get this one help me please

galina1969 [7]

...........................................................(4 yrd and 2ft ) there is 3 ft in a yard 14 divided by 3 is 4 remainder 2

6 0

3 years ago

Read 2 more answers

PLEASE HELP!! What is the scale factor?

mojhsa [17]

Answer:

Step-by-step explanation:

8 0

2 years ago

SOMEONE HELP ME PLS, I'M stuck on this one since yesterday!

AfilCa [17]

$\bf \begin{cases}
F = \{(0, 1), (\stackrel{x}{2}, \stackrel{y}{4}), (4, 6), (6, 8)\} & F(\stackrel{x}{2})=\stackrel{y}{4}
\\\\\\
G = \{(\stackrel{x}{2}, \stackrel{y}{5}), (4, 7), (5, 8), (6, 9), (7, 5)\} \qquad & G(\stackrel{x}{2})=\stackrel{y}{5}
\end{cases} 
\\\\\\
(F\cdot G)(2)\implies F(2)\cdot G(2)\implies 4\cdot 5\implies 20$

7 0

3 years ago