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Vesna [10]
3 years ago
5

Solve for x: 2x – y = (3/4)x + 6.

Mathematics
1 answer:
Artyom0805 [142]3 years ago
6 0

Answer:

B

Step-by-step explanation:

2x – y = (3/4)x + 6.

or, 2x - (3/4)x = y + 6.

or, (8x -3x)/4 = y + 6.

or, 5x/4 = y + 6.

or, 5x = 4(y + 6).

or, 5x = 4y + 24.

or, x = (4y + 24)/5.

Therefore, x = 4(y + 6)/5.

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How many sixths make a third? <br> help me out ‍
Vladimir [108]
One third = two sixths

1/6 + 1/6 = 1/3
7 0
3 years ago
1. Combine the like like terms<br> 14 + 8x + 2y -5x - 2
miss Akunina [59]

Answer:

12 + 3x + 2y

Step-by-step explanation:

14 + 8x + 2y -5x - 2

14 + -2 + 8x -5x + 2y

12 + 3x + 2y

7 0
3 years ago
Read 2 more answers
According to Reuters, a survey undertaken by the National Center for Health Statistics revealed that about 25% of U.S. household
ddd [48]

Answer:

a) P=0.8

b) P=0.67

c) P=0.05

d) P=0.33

e) P=0.45

Step-by-step explanation:

a. What is the probability that the household has only a cell phone and has high-speed Internet?

This probability is stated in the question: "Suppose of U.S. households having only a cell phone, 80% have high-speed Internet", so the probability is P=0.8.

P(C\&I)=0.8

b. What is the probability that the household has only a cell phone or has high-speed Internet?

This probability is equal to the sum of the probability of having only a cell phone and the probability of having high-speed internet, less the probability of having both (to avoid counting this household twice).

P(C\,orI\,)=P(C)+P(I)-P(C)*P(I|C)=0.25+0.65-(0.25*0.8)=0.25+0.62-0.20=0.67

c. What is the probability that the household has only a cell phone and does not have high-speed Internet?

This is equal to the probability of not having high-speed internet given that it has a cell phone (complementaty of the proability of Point (a)) multiplied by the probability of having a cell phone.

P(C\&\bar I)=P(\bar I|C)*P(C)=(1-P(\I|C))*P(C)=(1-0.8)*0.25 = 0.2*0.25 = 0.05

d. What is the probability that the household does not have just a cell phone and does not have high-speed Internet?

This probability is complementary of the one calculated in Point (c).

P(\bar C \,or\, \bar I)=1-P(C\, or\,I)=1-0.67=0.33

e. What is the probability that the household does not have just a cell phone and does have high-speed Internet?

This is equal to the probability of having high-speed internet less the probability it has both (cell phone and internet).

P(\bar C\&I)=P(I)-P(I|C)*P(C)=0.65-0.8*0.2=0.65-0.2=0.45

7 0
4 years ago
Find the following expression by multiplying <br> (A+b)^3
DaniilM [7]

Given expression: (A+b)^3.

We can expand it into three factors as (A+b)(A+b)(A+b).

First we would foil (A+b)(A+b) = A^2 + Ab+Ab+ b^2

Combining like terms, we get

= A^2 +2Ab + b^2

Now, we would multiply (A^2 +2Ab + b^2) and (A+b).

=A^3 + A^2b + 2A^2b+2Ab^2 + Ab^2+ b^3

Combining like terms, we get

=A^3+3A^2b+3Ab^2+b^3

Therefore,

\left(A+b\right)^3=\quad A^3+3A^2b+3Ab^2+b^3


8 0
3 years ago
A beetle is 1/5 inch wide and 2/5 inch long. How much greater is the beetle's length than its width?
Neporo4naja [7]

Answer:

2 times as long

Step-by-step explanation:

2/5 divded by 1/5 equals two

6 0
3 years ago
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