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12345 [234]
3 years ago
13

Help me with this SAT Question

SAT
1 answer:
never [62]3 years ago
7 0

Answer:

4pi/3

Explanation:

XY = YZ = XZ = 2

angle YXZ is pi/3

wxy is 2pi/3

Area of the circle = pi*r^2 = 4pi

Area of the shaded area = 4pi * (2pi/3)/(2pi) = 4pi/3

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the power output is the amount of gravitational potential energy being carried out by releasing electricity

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Where is more than two-thirds of earths fresh water sorted?
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<span> It's locked away in glaciers (in ice).</span>
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ANYONE KNOW ISABELA MONER/MERCED PHONE NUMBER
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1 212-867-5309

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go to google

6 0
3 years ago
Read 2 more answers
+23PTS! PDF Volume question -_- find diameter from the cylinder. I got 9 answer is 6 how???
Serga [27]

Answer: See below

Explanation:

For this question, we are given the volume, and we want to find the diameter. We have to work backwards to get our radius, then to find the diameter.

V=\pi r^2h         (Volume of cylinder)

72\pi =\pi r^2h      (The π cancel out)

72 =r^2(8)        (Plug in h=8)

9=r^2              (Divide 8)

r=3               (Square root of 9 is 3)

Now that we have our radius, we can find our diameter.

d=2r             (Equation for diameter)

d=2(3)\\          (Plug in r=3)

d=6yards     (Multiply)

5 0
3 years ago
Read 2 more answers
the height of a bottle rocket, in meters, is given by the function s(t)=−9t2+103t+403. find the average velocity of the bottle r
zaharov [31]

The average velocity of the bottle rocket are two given time intervals is 30 m/s and 20 m/s respectively, while the instantaneous velocity at 4.5 seconds is 22 m/s.

The given parameters;

  • s(t) = -9t² + 103t + 403
  • time interval (4.499, 4.5), and (4.5, 4.501)

The average velocity of the bottle rocket over the intervals is calculated as follows;

when the interval = [<em>4.499, 4.5</em>]

s(4.499)= -9(4.499)^2  + 103(4.499) + 403 = 684.22 \ m\\\\s(4.5) =  -9(4.5)^2  + 103(4.5) + 403 = 684.25 \ m

v = \frac{\Delta \ s}{\Delta \ t} = \frac{684.25 - 684.22}{4.5 - 4.499} = 30 \ m/s

when the interval = [<em>4.5, 4.501</em>]

s(4.5) = -9(4.5)^2 + 103(4.5) + 403 = 684.25 \ m\\\\s(4.501) = -9(4.501)^2 + 103(4.501) + 403 =684.27 \ m\\\\v= \frac{684.27 - 684.25}{4.501-4.5} \\\\v = 20 \ m/s

The instantaneous velocity of the bottle rocket at time t=4.5;

v = \frac{d \ s(t)}{dt} = -18t + 103\\\\v(4.5) = -18(4.5) + 103\\\\v(4.5) = 22 \ m/s

Thus, the average velocity of the bottle rocket are two given time intervals is 30 m/s and 20 m/s respectively, while the instantaneous velocity at 4.5 seconds is 22 m/s.

Learn more here: brainly.com/question/25009886

7 0
2 years ago
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