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marin [14]
3 years ago
11

You know that 125 is a composite number because it is divisible by ___. A. 2 B. 3 C. 5 D. 7

Mathematics
2 answers:
Marina86 [1]3 years ago
6 0

Well, since the last number in 125 is 5, it can't be divided by 2.

125 divided by 3 is 41.6 repeated, which isn't the correct answer.

125 divided by 7 is 17.85714285714286, which isn't a correct answer either.

So.. The answer is  C. 5

-Dominant- [34]3 years ago
4 0

The answer is C. 5

This is the answer because

125 / 2 = 62.5

125 / 3 = 41.6_

125 / 5 = 25

125 / 7 = 17.86

As you can see 5 is the only number it can be divisible by.

Hope that helps!!


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5 0
3 years ago
Jesse has $3.40 in quarters and nickels. The number of nickels is 5 more than 2 times the number of quarters. How many quarters
dlinn [17]

Answer:

9 quarters

Step-by-step explanation:

From the question

Jesse has $3.40 in quarters and nickels

Quarters = q = number of quarters

1 quarter = $0.25

nickels = n = number of nickels

1 nickel = $0.05

Hence,

0.25q + 0.05n = $3.40 .......Equation 1

The number of nickels is 5 more than 2 times the number of quarters.

n = 2q + 5

0.25q + 0.05n = $3.40 .......Equation 1

0.25q + 0.05(2q + 5) = 3.40

0.25q + 0.10q + 0.25= 3.40

0.35q = 3.40 - 0.25

0.35q = 3.15

q = 3.15/0.35

q = 9

Therefore, Jessie has 9 quarters.

3 0
3 years ago
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puteri [66]

Answer: I believe it's 6 5/8

Step-by-step explanation:

8 0
3 years ago
For the class of 2013's prom Norman's dress shop sold cheaper dresses for $90 each and more expensive dresses for $140 each. The
Tema [17]

Answer:

Number of cheaper dresses sold  is 35

Number of expensive  dresses sold  is 15

Step-by-step explanation:

Given:

Cost of cheaper dresses = $90

Cost of  expensive dresses = $140

Total cost of  the dresses = $5250

To Find:

Number of cheaper dress = ?

Number of expensive  dress = ?

Solution:

Let

The number of  cheaper dresses be x

The number of  expensive dresses be y

(Number of cheaper dresses X cost of cheap dress) +  (Number of Expensive dresses X cost of  expensive dress)  =  $5250

x \times90 +y \times 140 = 5250=  $5250

It is given that the 20 more of the cheaper dresses than the expensive dresses is sold

So,

number of cheaper dress  =  20  +  number of expensive dress

x = 20 + y---------------------------------------(1)

(20+y) \times90 +y \times 140 = 5250 = 5250

(20 \times 90 +y\times 90) +y \times 140= 5250

1800 + 90y+ 140y = 5250

1800 + 230y = 5250

230y =5250 -1800

230y = 3450

y = \frac{3450}{230}

y = 15

Substituting y in (1)

x = 20 +15

x= 35

5 0
3 years ago
A spieces of extremely rare, deep water fish are slowly becoming extinct. If there are a total of 821 of this type of fish and t
Step2247 [10]

Answer:

12 months in a year

6 is half a month so we're going off of 6 months.

So:

821*0.15= 123.15

821- 123.15= 697.85

697.85*0.15= 104.6775

697.85-104.6775= 593.1725

593.1725*0.15= 88.975875

593.1725-88.975875= 504.196625

504.196625 *0.15= 75.62949375

504.196625- 75.62949375= 428.56713125

428.56713125*0.15= 64.2850696875

428.56713125-64.2850696875 = 364.282061562

364.282061562*0.15= 54.6423092344

364.282061562-54.6423092344 = 309.639752328

So its 310 fish.

6 0
3 years ago
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