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sergiy2304 [10]
3 years ago
14

What is 5x + 11 - 2x = 17

Mathematics
2 answers:
tino4ka555 [31]3 years ago
5 0

Answer: x = 2

Step-by-step explanation:

5x + 11 - 2x = 17

Combine like terms

3x + 11 = 17

Subtract 11 from each side

3x = 6

Divide each side by 3

x = 2

In-s [12.5K]3 years ago
5 0
5x+11-2x=17
3x+11=17
3x=6
X=2
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How do I solve question 13 and 14?
xxMikexx [17]

Answer:

13. 13 or 17 (not sure about this, sorry)

14. 28

Step-by-step explanation:

13.

a_{n} = \{a_{0}, a_{1}, a_{2}, a_{3}, a_{4}, ... \} \\

if counting the sequence from a_{0} then a_{4} is 17, but if

a_{n} = \{a_{1}, a_{2}, a_{3}, a_{4}, a_{5}, ... \} \\

counting from a_{1}, then a_{4} is 13.

14.

a_{10} = 1 + 3(10 - 1) = 1 + 3*9 = 28

6 0
3 years ago
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Answer:

150.88

Step-by-step explanation:

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7 0
3 years ago
What is the value of: 1/2^-2x^-3y^5 for x=2 and y=-4
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3 years ago
Assume the hold time of callers to a cable company is normally distributed with a mean of 5.5 minutes and a standard deviation o
Ierofanga [76]

Answer:

The percent of callers are 37.21 who are on hold.

Step-by-step explanation:

Given:

A normally distributed data.

Mean of the data, \mu = 5.5 mins

Standard deviation, \sigma = 0.4 mins

We have to find the callers percentage who are on hold between 5.4 and 5.8 mins.

Lets find z-score on each raw score.

⇒ z_1=\frac{x_1-\mu}{\sigma}   ...raw score,x_1 = 5.4

⇒ Plugging the values.

⇒ z_1=\frac{5.4-5.5}{0.4}

⇒ z_1=-0.25  

For raw score 5.5 the z score is.

⇒ z_2=\frac{5.8-5.5}{0.4}  

⇒ z_2=0.75

Now we have to look upon the values from Z score table and arrange them in probability terms then convert it into percentages.

We have to work with P(5.4<z<5.8).

⇒ P(5.4

⇒ P(-0.25

⇒ P(z

⇒ z(1.5)=0.7734 and z(-0.25)=0.4013.<em>..from z -score table.</em>

⇒ 0.7734-0.4013

⇒ 0.3721

To find the percentage we have to multiply with 100.

⇒ 0.3721\times 100

⇒ 37.21 %

The percent of callers who are on hold between 5.4 minutes to 5.8 minutes is 37.21

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3 years ago
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ruslelena [56]

Answer:

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Step-by-step explanation:

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